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anonymous
 4 years ago
Prove: \[\huge S_n = \frac{n(a_n + a_1)}2\]
anonymous
 4 years ago
Prove: \[\huge S_n = \frac{n(a_n + a_1)}2\]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's an easy proof....but it's still nice to see some professional do it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i wrote that formula wrong...

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2See \[\S_n = \cfrac{n}{2} (2a + (n1)d)\]

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2Now put 2a +(n1)d = a + a+(n1)d = a_1 + a_n

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2You get ur answer !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i don't think that proves anything...that was formula transformation

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2see a_n = a+(n1)d

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2That really does //////////// :)

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2You don't want to use the first formula ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you prove a_n = a + (n1)d?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think you;re confused....this is proving...not substitution

shubhamsrg
 4 years ago
Best ResponseYou've already chosen the best response.1suppose we have 1,2,3,4.....100 adding all, we can see it like this (1+100) + (2+99) .... ( 50 + 51) => (101)*50 = (1 + 100) * (100/2) you may generalize this..

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2And u asked for a proof ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that wasn't a proof @vishweshshrimali5 ....it was formula transformation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and substitution isn't proving either.... @shubhamsrg

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2Whatever........... leave it I can prove that without using a_n formula

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2But you will have to accept that a_n = a+(n1)d That is basic def. of AP

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2I am also surprised @shubhamsrg O.o

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are any of you familiar with mathematical induction?

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2You want that proof........

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what both of you did was substitution (which is NEVER accepted as proofs)

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2Let P(n) be the given statement

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no. i want other proof

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0induction is too dull and boring and predictable

shubhamsrg
 4 years ago
Best ResponseYou've already chosen the best response.1you're amazing you know that ?

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2@lgbasallote please give us a "hint" of the proof u want

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0actually...it's surprising @vishweshshrimali5 does know induction...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0any proof as long as it's valid and not induction

shubhamsrg
 4 years ago
Best ResponseYou've already chosen the best response.1induction is one of the many great tools we have in mathematics today!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0preferrably, i like to see direct proof and contradiction

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i like deduction much more

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2Ok lets try u want to deduce a formula from a continuous pattern

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0time for the site to go down....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i suppose i'll just ask this again in the fture

vishweshshrimali5
 4 years ago
Best ResponseYou've already chosen the best response.2will check out later
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