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lgbasalloteBest ResponseYou've already chosen the best response.0
it's an easy proof....but it's still nice to see some professional do it
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i wrote that formula wrong...
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
See \[\S_n = \cfrac{n}{2} (2a + (n1)d)\]
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
Now put 2a +(n1)d = a + a+(n1)d = a_1 + a_n
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
You get ur answer !
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i don't think that proves anything...that was formula transformation
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
see a_n = a+(n1)d
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
That really does //////////// :)
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
You don't want to use the first formula ?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
can you prove a_n = a + (n1)d?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i think you;re confused....this is proving...not substitution
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
suppose we have 1,2,3,4.....100 adding all, we can see it like this (1+100) + (2+99) .... ( 50 + 51) => (101)*50 = (1 + 100) * (100/2) you may generalize this..
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
And u asked for a proof ;)
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
that wasn't a proof @vishweshshrimali5 ....it was formula transformation
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
and substitution isn't proving either.... @shubhamsrg
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
Whatever........... leave it I can prove that without using a_n formula
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
But you will have to accept that a_n = a+(n1)d That is basic def. of AP
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
I am also surprised @shubhamsrg O.o
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
are any of you familiar with mathematical induction?
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
You want that proof........
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
what both of you did was substitution (which is NEVER accepted as proofs)
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
Let P(n) be the given statement
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
no. i want other proof
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
induction is too dull and boring and predictable
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
you're amazing you know that ?
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
@lgbasallote please give us a "hint" of the proof u want
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
actually...it's surprising @vishweshshrimali5 does know induction...
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
any proof as long as it's valid and not induction
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
induction is one of the many great tools we have in mathematics today!
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
preferrably, i like to see direct proof and contradiction
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i like deduction much more
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
Ok lets try u want to deduce a formula from a continuous pattern
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
time for the site to go down....
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
so i suppose i'll just ask this again in the fture
 one year ago

vishweshshrimali5Best ResponseYou've already chosen the best response.2
will check out later
 one year ago
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