Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Prove: \[\huge S_n = \frac{n(a_n + a_1)}2\]

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

it's an easy proof....but it's still nice to see some professional do it
i wrote that formula wrong...
See \[\S_n = \cfrac{n}{2} (2a + (n-1)d)\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Now put 2a +(n-1)d = a + a+(n-1)d = a_1 + a_n
You get ur answer !
i don't think that proves anything...that was formula transformation
see a_n = a+(n-1)d
That really does //////////// :)
You don't want to use the first formula ?
can you prove a_n = a + (n-1)d?
I think yes
i think you;re confused....this is proving...not substitution
suppose we have 1,2,3,4.....100 adding all, we can see it like this (1+100) + (2+99) .... ( 50 + 51) => (101)*50 = (1 + 100) * (100/2) you may generalize this..
And u asked for a proof ;)
that wasn't a proof @vishweshshrimali5 was formula transformation
and substitution isn't proving either.... @shubhamsrg
Whatever........... leave it I can prove that without using a_n formula
substitution ? o.O
But you will have to accept that a_n = a+(n-1)d That is basic def. of AP
I am also surprised @shubhamsrg O.o
i am not! ;)
are any of you familiar with mathematical induction?
You want that proof........
what both of you did was substitution (which is NEVER accepted as proofs)
Let P(n) be the given statement
no. i want other proof
induction is too dull and boring and predictable
you're amazing you know that ?
not you ! ;)
@lgbasallote please give us a "hint" of the proof u want's surprising @vishweshshrimali5 does know induction...
hint? lol..
any proof as long as it's valid and not induction
induction is one of the many great tools we have in mathematics today!
preferrably, i like to see direct proof and contradiction
i like deduction much more
Ok lets try u want to deduce a formula from a continuous pattern
time for the site to go down....
so i suppose i'll just ask this again in the fture
will check out later

Not the answer you are looking for?

Search for more explanations.

Ask your own question