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lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
it's an easy proof....but it's still nice to see some professional do it
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i wrote that formula wrong...
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
See \[\S_n = \cfrac{n}{2} (2a + (n1)d)\]
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
Now put 2a +(n1)d = a + a+(n1)d = a_1 + a_n
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
You get ur answer !
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i don't think that proves anything...that was formula transformation
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
see a_n = a+(n1)d
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
That really does //////////// :)
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
You don't want to use the first formula ?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
can you prove a_n = a + (n1)d?
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
I think yes
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i think you;re confused....this is proving...not substitution
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
suppose we have 1,2,3,4.....100 adding all, we can see it like this (1+100) + (2+99) .... ( 50 + 51) => (101)*50 = (1 + 100) * (100/2) you may generalize this..
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
And u asked for a proof ;)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
that wasn't a proof @vishweshshrimali5 ....it was formula transformation
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
and substitution isn't proving either.... @shubhamsrg
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
Whatever........... leave it I can prove that without using a_n formula
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
substitution ? o.O
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
But you will have to accept that a_n = a+(n1)d That is basic def. of AP
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
I am also surprised @shubhamsrg O.o
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
i am not! ;)
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
;)
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
are any of you familiar with mathematical induction?
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
Yes
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
You want that proof........
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
what both of you did was substitution (which is NEVER accepted as proofs)
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
Let P(n) be the given statement
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
no. i want other proof
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
induction is too dull and boring and predictable
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
you're amazing you know that ?
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
not you ! ;)
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
@lgbasallote please give us a "hint" of the proof u want
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
actually...it's surprising @vishweshshrimali5 does know induction...
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
hint? lol..
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
any proof as long as it's valid and not induction
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
induction is one of the many great tools we have in mathematics today!
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
preferrably, i like to see direct proof and contradiction
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i like deduction much more
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
Ok lets try u want to deduce a formula from a continuous pattern
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
time for the site to go down....
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
bye
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so i suppose i'll just ask this again in the fture
 2 years ago

vishweshshrimali5 Group TitleBest ResponseYou've already chosen the best response.2
will check out later
 2 years ago
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