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jonzion1122 Group Title

3^X+3 - 9^2X-1=0 what are the steps to finding the solution?

  • 2 years ago
  • 2 years ago

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  1. myininaya Group Title
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    \[3^x+3-9^{2x}-1=0?\]

    • 2 years ago
  2. myininaya Group Title
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    Or! Do you mean \[3^{x+3}-9^{2x-1}=0\]

    • 2 years ago
  3. jonzion1122 Group Title
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    second one

    • 2 years ago
  4. myininaya Group Title
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    Ok did you add to both sides \[9^{2x+1}\]

    • 2 years ago
  5. myininaya Group Title
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    \[3^{x+2}=9^{2x+1}\]

    • 2 years ago
  6. myininaya Group Title
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    oops - not + oh well

    • 2 years ago
  7. myininaya Group Title
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    Do you know how to answer the following What number satisfies the equation \[9=3^{?}\]

    • 2 years ago
  8. myininaya Group Title
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    Ok great. So we have \[3^{x+2}=(3^{2})^{(2x-1)}\] since 3^2=9 :)

    • 2 years ago
  9. myininaya Group Title
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    So we have the same base on both sides All you need to do is set the exponents equal and solve for x

    • 2 years ago
  10. myininaya Group Title
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    \[x+2=2(2x-1)\]

    • 2 years ago
  11. myininaya Group Title
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    Let me know if you have further questions :)

    • 2 years ago
  12. jonzion1122 Group Title
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    firstly its x+3 but where did you get the 2 in "2"(2x-1)

    • 2 years ago
  13. myininaya Group Title
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    \[9=3^2 \] \[3^{x+3}=9^{2x-1}\] \[3^{x+2}=(3^2)^{(2x-1)}\]

    • 2 years ago
  14. jonzion1122 Group Title
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    how does 3^2(^2x-1) = 2(2x-1)

    • 2 years ago
  15. myininaya Group Title
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    No....we have x+2=2(2x-1) not what you wrote

    • 2 years ago
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