Find, by induction, the n:th derivitive of
\[\frac{ x ^{2}+2x-3 }{ 4x+4 }\]
I've counted the 4 first derivitives which are:
1. \[\frac{ x ^{2}+2x+5 }{ 4(x+1)^{2} }\]
2. \[\frac{ -2 }{ (x+1)^{3} }\]
3. \[\frac{ 6 }{ (x+1)^{4} }\]
4. \[\frac{ -24 }{ (x+1)^{5} }\]
5. \[\frac{ (-1)^{n+1}*?*n }{ (x+1)^{n+1} } \]
I don't really know if i'm on the right track cause i didn't find the n:th derivitive by induction..

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Ok so good so far...you have the 1st derivative right...
Okay...checking your second

Great!

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