• anonymous
Find, by induction, the n:th derivitive of $\frac{ x ^{2}+2x-3 }{ 4x+4 }$ I've counted the 4 first derivitives which are: 1. $\frac{ x ^{2}+2x+5 }{ 4(x+1)^{2} }$ 2. $\frac{ -2 }{ (x+1)^{3} }$ 3. $\frac{ 6 }{ (x+1)^{4} }$ 4. $\frac{ -24 }{ (x+1)^{5} }$ 5. $\frac{ (-1)^{n+1}*?*n }{ (x+1)^{n+1} }$ I don't really know if i'm on the right track cause i didn't find the n:th derivitive by induction..
Geometry

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