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Let z be a complex number such that imaginary part of z is non zero and a=z^2+z+1 is real then a cannot take the value?
 one year ago
 one year ago
Yahoo! Group Title
Let z be a complex number such that imaginary part of z is non zero and a=z^2+z+1 is real then a cannot take the value?
 one year ago
 one year ago

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mukushla Group TitleBest ResponseYou've already chosen the best response.1
z=x+iy evaluate the value of a in terms of x and y
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
x^2 + 2xiy  y^2 + x + iy + 1 = a
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
\(y\neq0\) and\[2xy+y=0\]right?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Why? 2xy + y =0
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
because a is a real number
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
got it.....
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
2xy+y=0 and \(y\neq0\) so\[2x+1=0\]
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
do u know why \(y\neq0\)
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
if y=0 then imaginary part becomes 0
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
\[x=\frac{1}{2}\]so a becomes\[a=\frac{3}{4}y^2\]am i right?
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
so whats the value that a can not take considering \(y\neq0\) clearly\[a\neq\frac{3}{4}\]we are done :)
 one year ago
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