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nexis
 3 years ago
In 4a)
http://ocw.mit.edu/courses/mathematics/1801scsinglevariablecalculusfall2010/exam3/materialsforexam3/MIT18_01SCF10_exam3sol.pdf
How do we find the formula for hypotenuse of the triangle?
(hhx/r)
(Just for x)
(Sorry, somehow this question got closed before)
nexis
 3 years ago
In 4a) http://ocw.mit.edu/courses/mathematics/1801scsinglevariablecalculusfall2010/exam3/materialsforexam3/MIT18_01SCF10_exam3sol.pdf How do we find the formula for hypotenuse of the triangle? (hhx/r) (Just for x) (Sorry, somehow this question got closed before)

This Question is Closed

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1you ask how they got y = h hx/r ?

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1we have two points : ( 0,h) and (r,0)

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1hence the slope : (h0) /(0r) = h/r and using y = y1 + m(xx1) we get : y = h hx/r

nexis
 3 years ago
Best ResponseYou've already chosen the best response.0sorry, why are we using h for y1?

nexis
 3 years ago
Best ResponseYou've already chosen the best response.0i can see how we get the slope

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1we can take one of the points : (0,h) or (r,0) to be (x1,y1) in both cases we will get the same answer

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1lets take the (r,0) so y1 = 0 : y = 0 + h/r(xr) y = h hx/r

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1we find slope then we can choose any given point on the line to construct our line equation :)
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