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nexis
Group Title
In 4a)
http://ocw.mit.edu/courses/mathematics/1801scsinglevariablecalculusfall2010/exam3/materialsforexam3/MIT18_01SCF10_exam3sol.pdf
How do we find the formula for hypotenuse of the triangle?
(hhx/r)
(Just for x)
(Sorry, somehow this question got closed before)
 one year ago
 one year ago
nexis Group Title
In 4a) http://ocw.mit.edu/courses/mathematics/1801scsinglevariablecalculusfall2010/exam3/materialsforexam3/MIT18_01SCF10_exam3sol.pdf How do we find the formula for hypotenuse of the triangle? (hhx/r) (Just for x) (Sorry, somehow this question got closed before)
 one year ago
 one year ago

This Question is Closed

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
you ask how they got y = h hx/r ?
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
we have two points : ( 0,h) and (r,0)
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
hence the slope : (h0) /(0r) = h/r and using y = y1 + m(xx1) we get : y = h hx/r
 one year ago

nexis Group TitleBest ResponseYou've already chosen the best response.0
sorry, why are we using h for y1?
 one year ago

nexis Group TitleBest ResponseYou've already chosen the best response.0
i can see how we get the slope
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
we can take one of the points : (0,h) or (r,0) to be (x1,y1) in both cases we will get the same answer
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
lets take the (r,0) so y1 = 0 : y = 0 + h/r(xr) y = h hx/r
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
we find slope then we can choose any given point on the line to construct our line equation :)
 one year ago

nexis Group TitleBest ResponseYou've already chosen the best response.0
great, got it, thanks :)
 one year ago
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