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frx

  • 2 years ago

If one uses implicit differentiation and get that \[y^'=\frac{ 2x^3-x }{ 2y^3-y }\] Then is the slope of the tangent line at point (x,y) given by just putting the x and y into the equation?

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  1. frx
    • 2 years ago
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    @ghazi

  2. ghazi
    • 2 years ago
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    wait a sec bro?

  3. frx
    • 2 years ago
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    Absolutely

  4. phi
    • 2 years ago
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    if you mean x,y have known values, yes, plug them in to find the slope at that point on the curve.

  5. frx
    • 2 years ago
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    That was what i meant, thank you :)

  6. frx
    • 2 years ago
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    ghazi, I guess you went to look it up or something so thank you to :)

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