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burhan101
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\[\lim_{x \rightarrow 2} \frac{ x^24 }{ \sqrt{x2} }\]

burhan101
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without making the squareroot into an exponent how would i solve ?

ksaimouli
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what about rationalizing the denominator

burhan101
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can you please explain that to me? i honestly don't see it

burhan101
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the square root is complicating it for me

ksaimouli
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dw:1350435858610:dw

ksaimouli
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but the exponential form is the best way to do it

burhan101
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ohh we cant do that .. i did that too but my teacher said that since they are not binomials we cannot multiply by the conjugates

anonymous
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not quite right

anonymous
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rationalize the denominator in this case means multiply top and bottom by
\[\sqrt{x2}\]

anonymous
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your denominator will be \(x2\) which will cancel with on of the factors in the numerator

ksaimouli
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so what i steh answer

burhan101
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i dont get it, why would you multiply top ad bottom by the square root ?

burhan101
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ohh because it's the denominator ?

ksaimouli
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yup

ksaimouli
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to cancel the square root