anonymous
  • anonymous
Limits
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\lim_{x \rightarrow 2} \frac{ x^2-4 }{ \sqrt{x-2} }\]
anonymous
  • anonymous
without making the squareroot into an exponent how would i solve ?
ksaimouli
  • ksaimouli
what about rationalizing the denominator

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anonymous
  • anonymous
can you please explain that to me? i honestly don't see it
anonymous
  • anonymous
the square root is complicating it for me
ksaimouli
  • ksaimouli
|dw:1350435858610:dw|
ksaimouli
  • ksaimouli
but the exponential form is the best way to do it
anonymous
  • anonymous
ohh we cant do that .. i did that too but my teacher said that since they are not binomials we cannot multiply by the conjugates
anonymous
  • anonymous
not quite right
anonymous
  • anonymous
rationalize the denominator in this case means multiply top and bottom by \[\sqrt{x-2}\]
anonymous
  • anonymous
your denominator will be \(x-2\) which will cancel with on of the factors in the numerator
ksaimouli
  • ksaimouli
so what i steh answer
anonymous
  • anonymous
i dont get it, why would you multiply top ad bottom by the square root ?
anonymous
  • anonymous
ohh because it's the denominator ?
ksaimouli
  • ksaimouli
yup
ksaimouli
  • ksaimouli
to cancel the square root

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