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burhan101

  • 2 years ago

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  1. burhan101
    • 2 years ago
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    \[\lim_{x \rightarrow 2} \frac{ x^2-4 }{ \sqrt{x-2} }\]

  2. burhan101
    • 2 years ago
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    without making the squareroot into an exponent how would i solve ?

  3. ksaimouli
    • 2 years ago
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    what about rationalizing the denominator

  4. burhan101
    • 2 years ago
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    can you please explain that to me? i honestly don't see it

  5. burhan101
    • 2 years ago
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    the square root is complicating it for me

  6. ksaimouli
    • 2 years ago
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    |dw:1350435858610:dw|

  7. ksaimouli
    • 2 years ago
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    but the exponential form is the best way to do it

  8. burhan101
    • 2 years ago
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    ohh we cant do that .. i did that too but my teacher said that since they are not binomials we cannot multiply by the conjugates

  9. satellite73
    • 2 years ago
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    not quite right

  10. satellite73
    • 2 years ago
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    rationalize the denominator in this case means multiply top and bottom by \[\sqrt{x-2}\]

  11. satellite73
    • 2 years ago
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    your denominator will be \(x-2\) which will cancel with on of the factors in the numerator

  12. ksaimouli
    • 2 years ago
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    so what i steh answer

  13. burhan101
    • 2 years ago
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    i dont get it, why would you multiply top ad bottom by the square root ?

  14. burhan101
    • 2 years ago
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    ohh because it's the denominator ?

  15. ksaimouli
    • 2 years ago
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    yup

  16. ksaimouli
    • 2 years ago
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    to cancel the square root

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