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burhan101
 3 years ago
Limits
burhan101
 3 years ago
Limits

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burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 2} \frac{ x^24 }{ \sqrt{x2} }\]

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0without making the squareroot into an exponent how would i solve ?

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0what about rationalizing the denominator

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0can you please explain that to me? i honestly don't see it

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0the square root is complicating it for me

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350435858610:dw

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0but the exponential form is the best way to do it

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0ohh we cant do that .. i did that too but my teacher said that since they are not binomials we cannot multiply by the conjugates

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1rationalize the denominator in this case means multiply top and bottom by \[\sqrt{x2}\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1your denominator will be \(x2\) which will cancel with on of the factors in the numerator

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0so what i steh answer

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0i dont get it, why would you multiply top ad bottom by the square root ?

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0ohh because it's the denominator ?

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0to cancel the square root
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