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\[\lim_{x \rightarrow 2} \frac{ x^2-4 }{ \sqrt{x-2} }\]
without making the squareroot into an exponent how would i solve ?
what about rationalizing the denominator

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Other answers:

can you please explain that to me? i honestly don't see it
the square root is complicating it for me
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but the exponential form is the best way to do it
ohh we cant do that .. i did that too but my teacher said that since they are not binomials we cannot multiply by the conjugates
not quite right
rationalize the denominator in this case means multiply top and bottom by \[\sqrt{x-2}\]
your denominator will be \(x-2\) which will cancel with on of the factors in the numerator
so what i steh answer
i dont get it, why would you multiply top ad bottom by the square root ?
ohh because it's the denominator ?
yup
to cancel the square root

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