## blast234 3 years ago Need help on solving three system of equations using substitution? -x-y-z=-9 -5x+5y+6z=8 3x+3z=5 I really need help...

1. blast234

This is confusing....

2. blast234

3. liza2

x-y-z=-9 z = -9 -x + y Using this: 3x+3z=5 3x + 3(-9 -x +y) = 5 3x -27 -3x +3y = 5 3y - 27 = 5 3y = 32 y = 32/3 x - 32/3 - (-9 - x + 32/3) = -9 x - 32/3 + 9 + x - 32/3 = -9 2x - 12.3 = -9 2x = 3.3 x = 1 2/3 z = -9 - 1 2/3 + 32/3 z = 0 1 2/3 - 32/3 - 0 = -9

4. blast234

Thanks for helping

5. blast234

R u sure these how you do them

6. chance327

Best Response 0 x-y-z=-9 z = -9 -x + y Using this: 3x+3z=5 3x + 3(-9 -x +y) = 5 3x -27 -3x +3y = 5 3y - 27 = 5 3y = 32 y = 32/3 x - 32/3 - (-9 - x + 32/3) = -9 x - 32/3 + 9 + x - 32/3 = -9 2x - 12.3 = -9 2x = 3.3 x = 1 2/3 z = -9 - 1 2/3 + 32/3 z = 0 1 2/3 - 32/3 - 0 = -9

7. blast234

Thanks

8. chance327

welcome

9. blast234

That was quick

10. chance327

yep

11. blast234

Can you add her people as friends

12. blast234

here

13. chance327

14. blast234

Oh nothing..never mind

15. chance327

oh ok

16. blast234

How did you get 12.3

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