blast234
Need help on solving three system of equations using substitution?
xyz=9
5x+5y+6z=8
3x+3z=5
I really need help...



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blast234
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This is confusing....

blast234
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Somebody please help me...

liza2
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xyz=9
z = 9 x + y
Using this:
3x+3z=5
3x + 3(9 x +y) = 5
3x 27 3x +3y = 5
3y  27 = 5
3y = 32
y = 32/3
x  32/3  (9  x + 32/3) = 9
x  32/3 + 9 + x  32/3 = 9
2x  12.3 = 9
2x = 3.3
x = 1 2/3
z = 9  1 2/3 + 32/3
z = 0
1 2/3  32/3  0 = 9

blast234
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Thanks for helping

blast234
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R u sure these how you do them

chance327
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xyz=9
z = 9 x + y
Using this:
3x+3z=5
3x + 3(9 x +y) = 5
3x 27 3x +3y = 5
3y  27 = 5
3y = 32
y = 32/3
x  32/3  (9  x + 32/3) = 9
x  32/3 + 9 + x  32/3 = 9
2x  12.3 = 9
2x = 3.3
x = 1 2/3
z = 9  1 2/3 + 32/3
z = 0
1 2/3  32/3  0 = 9

blast234
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Thanks

chance327
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welcome

blast234
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That was quick

chance327
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yep

blast234
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Can you add her people as friends

blast234
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here

chance327
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who you talking about

blast234
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Oh nothing..never mind

chance327
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oh ok

blast234
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How did you get 12.3