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blast234

Need help on solving three system of equations using substitution? -x-y-z=-9 -5x+5y+6z=8 3x+3z=5 I really need help...

  • one year ago
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  1. blast234
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    This is confusing....

    • one year ago
  2. blast234
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    Somebody please help me...

    • one year ago
  3. liza2
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    x-y-z=-9 z = -9 -x + y Using this: 3x+3z=5 3x + 3(-9 -x +y) = 5 3x -27 -3x +3y = 5 3y - 27 = 5 3y = 32 y = 32/3 x - 32/3 - (-9 - x + 32/3) = -9 x - 32/3 + 9 + x - 32/3 = -9 2x - 12.3 = -9 2x = 3.3 x = 1 2/3 z = -9 - 1 2/3 + 32/3 z = 0 1 2/3 - 32/3 - 0 = -9

    • one year ago
  4. blast234
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    Thanks for helping

    • one year ago
  5. blast234
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    R u sure these how you do them

    • one year ago
  6. chance327
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    Best Response 0 x-y-z=-9 z = -9 -x + y Using this: 3x+3z=5 3x + 3(-9 -x +y) = 5 3x -27 -3x +3y = 5 3y - 27 = 5 3y = 32 y = 32/3 x - 32/3 - (-9 - x + 32/3) = -9 x - 32/3 + 9 + x - 32/3 = -9 2x - 12.3 = -9 2x = 3.3 x = 1 2/3 z = -9 - 1 2/3 + 32/3 z = 0 1 2/3 - 32/3 - 0 = -9

    • one year ago
  7. blast234
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    Thanks

    • one year ago
  8. chance327
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    welcome

    • one year ago
  9. blast234
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    That was quick

    • one year ago
  10. chance327
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    yep

    • one year ago
  11. blast234
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    Can you add her people as friends

    • one year ago
  12. blast234
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    here

    • one year ago
  13. chance327
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    who you talking about

    • one year ago
  14. blast234
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    Oh nothing..never mind

    • one year ago
  15. chance327
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    oh ok

    • one year ago
  16. blast234
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    How did you get 12.3

    • one year ago
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