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blast234

  • 3 years ago

Need help on solving three system of equations using substitution? -x-y-z=-9 -5x+5y+6z=8 3x+3z=5 I really need help...

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  1. blast234
    • 3 years ago
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    This is confusing....

  2. blast234
    • 3 years ago
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    Somebody please help me...

  3. liza2
    • 3 years ago
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    x-y-z=-9 z = -9 -x + y Using this: 3x+3z=5 3x + 3(-9 -x +y) = 5 3x -27 -3x +3y = 5 3y - 27 = 5 3y = 32 y = 32/3 x - 32/3 - (-9 - x + 32/3) = -9 x - 32/3 + 9 + x - 32/3 = -9 2x - 12.3 = -9 2x = 3.3 x = 1 2/3 z = -9 - 1 2/3 + 32/3 z = 0 1 2/3 - 32/3 - 0 = -9

  4. blast234
    • 3 years ago
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    Thanks for helping

  5. blast234
    • 3 years ago
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    R u sure these how you do them

  6. chance327
    • 3 years ago
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    Best Response 0 x-y-z=-9 z = -9 -x + y Using this: 3x+3z=5 3x + 3(-9 -x +y) = 5 3x -27 -3x +3y = 5 3y - 27 = 5 3y = 32 y = 32/3 x - 32/3 - (-9 - x + 32/3) = -9 x - 32/3 + 9 + x - 32/3 = -9 2x - 12.3 = -9 2x = 3.3 x = 1 2/3 z = -9 - 1 2/3 + 32/3 z = 0 1 2/3 - 32/3 - 0 = -9

  7. blast234
    • 3 years ago
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    Thanks

  8. chance327
    • 3 years ago
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    welcome

  9. blast234
    • 3 years ago
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    That was quick

  10. chance327
    • 3 years ago
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    yep

  11. blast234
    • 3 years ago
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    Can you add her people as friends

  12. blast234
    • 3 years ago
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    here

  13. chance327
    • 3 years ago
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    who you talking about

  14. blast234
    • 3 years ago
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    Oh nothing..never mind

  15. chance327
    • 3 years ago
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    oh ok

  16. blast234
    • 3 years ago
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    How did you get 12.3

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