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burhan101

  • 3 years ago

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  1. burhan101
    • 3 years ago
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    my factors arent cancelling out

  2. burhan101
    • 3 years ago
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    \[\lim_{x \rightarrow -3}\frac{ x^2+5x+6 }{ x^2-x-12 }\]

  3. TuringTest
    • 3 years ago
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    then you factored wrong...

  4. malevolence19
    • 3 years ago
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    \[= \lim_{x \rightarrow -3} \frac{(x+3)(x+2)}{(x-4)(x+3)}=\lim_{x \rightarrow -3}\frac{x+2}{x-4}=1/7\]

  5. burhan101
    • 3 years ago
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    im getting this but ot sure how ? \[\lim_{x \rightarrow -2}\frac{ x^2+2x+3x+6 }{ x^2-3x+4x-12 }\]

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