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burhan101
Limits
my factors arent cancelling out
\[\lim_{x \rightarrow -3}\frac{ x^2+5x+6 }{ x^2-x-12 }\]
then you factored wrong...
\[= \lim_{x \rightarrow -3} \frac{(x+3)(x+2)}{(x-4)(x+3)}=\lim_{x \rightarrow -3}\frac{x+2}{x-4}=1/7\]
im getting this but ot sure how ? \[\lim_{x \rightarrow -2}\frac{ x^2+2x+3x+6 }{ x^2-3x+4x-12 }\]