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\[\lim_{x \rightarrow -1} \sqrt{\frac{ 1-t^2 }{ 1+t }}\]

why is your limit has x approahing -1 and the function is in terms of t?

that was a typo an my behalf :$

factor the numerator to (1+t)(1-t) then cancel the (1+t) out so you are left with
\[\sqrt{1-t}\]

then you can substitue

@kphilips2010 that method is not correct

i dont think i ca use conjugates for this question

why is that wrong?

because it's not a binomia

binomial*

they are not conjugates, they are addition and addition is commutative

I didnt say it was a binomial, I am saying you can factor the binomial into (1+t)(1-t)

but isnt there another method, like multiply by the denominator or something of the like

no not in this case

LOL i am sure I am right...I hope

kphilips method is good imo.

thanks joemath314159

i know thats how i approached the question at first but my teacher said this method was wrong ? :S

hmmm I feel dumb

why did your teacher say you were wrong?

i dont know she said there was something wrong with the method :S

does she know what she is talking about? LOL

sorry but i dont have another solution

is this what you're saying |dw:1350442853605:dw|

so do i keep the square root sign ?

ohh i see what you're saying

does the squareroot say there tho ?

yes.

yes the sq rt stay

yay i was right.

thanks :D