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anonymous
 3 years ago
limit
anonymous
 3 years ago
limit

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 1} \sqrt{\frac{ 1t^2 }{ 1+t }}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why is your limit has x approahing 1 and the function is in terms of t?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that was a typo an my behalf :$

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0factor the numerator to (1+t)(1t) then cancel the (1+t) out so you are left with \[\sqrt{1t}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then you can substitue

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@kphilips2010 that method is not correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont think i ca use conjugates for this question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because it's not a binomia

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0they are not conjugates, they are addition and addition is commutative

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I didnt say it was a binomial, I am saying you can factor the binomial into (1+t)(1t)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but isnt there another method, like multiply by the denominator or something of the like

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0LOL i am sure I am right...I hope

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0kphilips method is good imo.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know thats how i approached the question at first but my teacher said this method was wrong ? :S

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why did your teacher say you were wrong?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont know she said there was something wrong with the method :S

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does she know what she is talking about? LOL

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry but i dont have another solution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is this what you're saying dw:1350442853605:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so do i keep the square root sign ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you want to be rigorous about it, you need to state that for limits, you are looking at values of t close to 1, but NOT EQUAL to 1. if t is not equal to 1, then:\[\frac{1t^2}{1+t}=\frac{(1t)(1+t)}{(1+t)}=1t\]We can only divide those monomials out if t DOESNT equal 1, which is ok in limits, we dont want t to equal 1. Im making an emphasis on the fact that if t was equal to 1, then that division doesnt make any sense.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh i see what you're saying

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does the squareroot say there tho ?
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