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burhan101

limit

  • one year ago
  • one year ago

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  1. burhan101
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    \[\lim_{x \rightarrow -1} \sqrt{\frac{ 1-t^2 }{ 1+t }}\]

    • one year ago
  2. kphilips2010
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    why is your limit has x approahing -1 and the function is in terms of t?

    • one year ago
  3. burhan101
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    that was a typo an my behalf :$

    • one year ago
  4. kphilips2010
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    factor the numerator to (1+t)(1-t) then cancel the (1+t) out so you are left with \[\sqrt{1-t}\]

    • one year ago
  5. kphilips2010
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    then you can substitue

    • one year ago
  6. burhan101
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    @kphilips2010 that method is not correct

    • one year ago
  7. burhan101
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    i dont think i ca use conjugates for this question

    • one year ago
  8. kphilips2010
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    why is that wrong?

    • one year ago
  9. burhan101
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    because it's not a binomia

    • one year ago
  10. burhan101
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    binomial*

    • one year ago
  11. kphilips2010
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    they are not conjugates, they are addition and addition is commutative

    • one year ago
  12. kphilips2010
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    I didnt say it was a binomial, I am saying you can factor the binomial into (1+t)(1-t)

    • one year ago
  13. burhan101
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    but isnt there another method, like multiply by the denominator or something of the like

    • one year ago
  14. kphilips2010
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    no not in this case

    • one year ago
  15. kphilips2010
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    LOL i am sure I am right...I hope

    • one year ago
  16. joemath314159
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    kphilips method is good imo.

    • one year ago
  17. kphilips2010
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    thanks joemath314159

    • one year ago
  18. burhan101
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    i know thats how i approached the question at first but my teacher said this method was wrong ? :S

    • one year ago
  19. kphilips2010
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    hmmm I feel dumb

    • one year ago
  20. kphilips2010
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    why did your teacher say you were wrong?

    • one year ago
  21. burhan101
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    i dont know she said there was something wrong with the method :S

    • one year ago
  22. kphilips2010
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    does she know what she is talking about? LOL

    • one year ago
  23. kphilips2010
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    sorry but i dont have another solution

    • one year ago
  24. burhan101
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    is this what you're saying |dw:1350442853605:dw|

    • one year ago
  25. burhan101
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    so do i keep the square root sign ?

    • one year ago
  26. joemath314159
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    If you want to be rigorous about it, you need to state that for limits, you are looking at values of t close to -1, but NOT EQUAL to -1. if t is not equal to -1, then:\[\frac{1-t^2}{1+t}=\frac{(1-t)(1+t)}{(1+t)}=1-t\]We can only divide those monomials out if t DOESNT equal -1, which is ok in limits, we dont want t to equal -1. Im making an emphasis on the fact that if t was equal to -1, then that division doesnt make any sense.

    • one year ago
  27. burhan101
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    ohh i see what you're saying

    • one year ago
  28. burhan101
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    does the squareroot say there tho ?

    • one year ago
  29. joemath314159
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    yes.

    • one year ago
  30. kphilips2010
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    yes the sq rt stay

    • one year ago
  31. kphilips2010
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    yay i was right.

    • one year ago
  32. burhan101
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    thanks :D

    • one year ago
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