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isnt y = <-6?
what do u mean?
these are my answers y<-3 d≥ - 6 s < 2 d< - 3
this is not an equation. you have to keep your signs. for the second question, when you divide by a negative number, the sign flips. so \[d \le -6\]
i know one of them is wrong because one doesnt match my graph
flip the sign for the second one and it will be correct
i got 2 -3 and i only have one -3 graph
hold on ill show u the graphs
when you dealing with this, dont you need to make to problems. for example, y/2 < -3 and another one like y/2>3
the 1st one is wrong
okay so the first graph is the y/2 - 3?
now i confused mysef
yea but you need to set 2 inequalities
what one is - 6?
im completely lost now
both question 1 and 2. the 1st one is open circle and the second one is a close circle
like look at my graphs what eqautions go wiht witch
i know that
so number 1 is also 6?
so what is 8d + 2 < 5d - 7?
nvm i got it thankss!