please help!; Assuming additivity of volumes, what is the concentration of KBr(in moles/L) in a solution prepared by mixing 2.50x10^2 of 0.0600 Molarity of KBr with 5.00x10^2 ml of 0.0830 Molarity?

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is the first one in mL too?

yea the 2.50x10^2 is in ml

I think this is how you do it. 1st: change the mL into L (since M is in mol/L) 2nd: calculate the number of moles of KBr in each solution (M * L from above) 3rd: add the 2 numbers for moles together 4th: add the 2 numbers for volume together 5th: divide since you now have total moles and total volume (M = moles/L)

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