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burhan101Best ResponseYou've already chosen the best response.0
\[\lim_{h \rightarrow 0}\frac{ \frac{ 4 }{ 2+2h }2 }{ h }\]
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
dw:1350448824402:dw
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
maybe reducing it all to just one fraction might help
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
dw:1350449555332:dw i know im doing something wrong
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
find a CD in the numerator .
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.0
\[\huge \frac{ \frac{ 42(2+2h) }{ 2+2h } }{h }\]
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+2h}2}{h}\] is the same as \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+2h}\frac{2(2+2h)}{2+2h}}{h}\] and further... \[\huge \lim_{h \rightarrow 0}\frac{\frac{4h}{2+2h}}{h}\]
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
Now reduce it to one fraction, and do any cancellations, if possible
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
why is it \[\frac{ 4x }{ 2+2h }\]
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
its supposed to be (2+h) *
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
Looked at your first post... Ok, then \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}2}{h}\]\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}\frac{2(2+h)}{2+h}}{h}\] \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}\frac{4+2h}{2+h}}{h}\]
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
yup limit approaches to 2 as x approaches to zero
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
@mark_o. You might want to reconsider..., given that there was a correction; it's 2+h, not 2+2h as was in the first post.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
sorry typing error :$
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
dw:1350450481516:dw why do i get this :S this doesnt make sense because that would mean the answer is zero
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
like what am i doing wrong?
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
You were to multiply \[\frac{2+h}{2+h}\] to the 2 in the numerator; not to the entire fraction.
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
that among other things... But yeah, multiply the \[\frac{2+h}{2+h}\] only to the 2, and redo your work...
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
but that doesnt get rid of the fraction
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
hmm @terenzreignz, i didnt see the first posting of 2+h, i only saw 2+2h,, ththnx for reminding though...:D
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
We're not to get rid of it, only to make it simpler, ie, only one fraction bar.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
dw:1350450882525:dw like that ?
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
That's right. Please continue.... :)
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
Just distribute the 2.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
dw:1350451064789:dw
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
ok... I think I know where you're getting at... Be careful, the way you wrote it is full of... difficulties. On top, you should have 4  (4 + 2h) Groupings can make a world of difference, so you better specify which operations are prioritised...
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.0
Not to mention you may have ignored and/or forgotten that there is another h in the denominator. Careful...
 one year ago
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