Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

burhan101

  • 2 years ago

limit

  • This Question is Closed
  1. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\lim_{h \rightarrow 0}\frac{ \frac{ 4 }{ 2+2h }-2 }{ h }\]

  2. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350448824402:dw|

  3. mark_o.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    limit approaches -2

  4. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no it approaches 0

  5. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    maybe reducing it all to just one fraction might help

  6. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350449555332:dw| i know im doing something wrong

  7. Algebraic!
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    find a CD in the numerator .

  8. Algebraic!
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\huge \frac{ \frac{ 4-2(2+2h) }{ 2+2h } }{h }\]

  9. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+2h}-2}{h}\] is the same as \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+2h}-\frac{2(2+2h)}{2+2h}}{h}\] and further... \[\huge \lim_{h \rightarrow 0}-\frac{\frac{4h}{2+2h}}{h}\]

  10. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Now reduce it to one fraction, and do any cancellations, if possible

  11. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why is it \[\frac{ 4x }{ 2+2h }\]

  12. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its supposed to be (2+h) *

  13. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Looked at your first post... Ok, then \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}-2}{h}\]\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}-\frac{2(2+h)}{2+h}}{h}\] \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}-\frac{4+2h}{2+h}}{h}\]

  14. mark_o.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yup limit approaches to -2 as x approaches to zero

  15. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @mark_o. You might want to reconsider..., given that there was a correction; it's 2+h, not 2+2h as was in the first post.

  16. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sorry typing error :$

  17. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350450481516:dw| why do i get this :S this doesnt make sense because that would mean the answer is zero

  18. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    like what am i doing wrong?

  19. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You were to multiply \[\frac{2+h}{2+h}\] to the -2 in the numerator; not to the entire fraction.

  20. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that among other things... But yeah, multiply the \[\frac{2+h}{2+h}\] only to the -2, and redo your work...

  21. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but that doesnt get rid of the fraction

  22. mark_o.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    hmm @terenzreignz, i didnt see the first posting of 2+h, i only saw 2+2h,, ththnx for reminding though...:D

  23. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    We're not to get rid of it, only to make it simpler, ie, only one fraction bar.

  24. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350450882525:dw| like that ?

  25. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That's right. Please continue.... :)

  26. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    cross multiply?

  27. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    nvm doesnt matter

  28. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Just distribute the 2.

  29. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1350451064789:dw|

  30. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok... I think I know where you're getting at... Be careful, the way you wrote it is full of... difficulties. On top, you should have 4 - (4 + 2h) Groupings can make a world of difference, so you better specify which operations are prioritised...

  31. terenzreignz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Not to mention you may have ignored and/or forgotten that there is another h in the denominator. Careful...

  32. burhan101
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohh alright !

  33. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.