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\[\lim_{h \rightarrow 0}\frac{ \frac{ 4 }{ 2+2h }-2 }{ h }\]

|dw:1350448824402:dw|

limit approaches -2

no it approaches 0

maybe reducing it all to just one fraction might help

|dw:1350449555332:dw| i know im doing something wrong

find a CD in the numerator .

\[\huge \frac{ \frac{ 4-2(2+2h) }{ 2+2h } }{h }\]

Now reduce it to one fraction, and do any cancellations, if possible

why is it \[\frac{ 4x }{ 2+2h }\]

its supposed to be (2+h) *

yup limit approaches to -2 as x approaches to zero

sorry typing error :$

like what am i doing wrong?

You were to multiply
\[\frac{2+h}{2+h}\]
to the -2 in the numerator; not to the entire fraction.

but that doesnt get rid of the fraction

We're not to get rid of it, only to make it simpler, ie, only one fraction bar.

|dw:1350450882525:dw| like that ?

That's right. Please continue.... :)

cross multiply?

nvm doesnt matter

Just distribute the 2.

|dw:1350451064789:dw|

ohh alright !