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burhan101
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\[\lim_{h \rightarrow 0}\frac{ \frac{ 4 }{ 2+2h }-2 }{ h }\]
burhan101
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|dw:1350448824402:dw|
mark_o.
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limit approaches -2
burhan101
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no it approaches 0
terenzreignz
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maybe reducing it all to just one fraction might help
burhan101
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|dw:1350449555332:dw| i know im doing something wrong
Algebraic!
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find a CD in the numerator .
Algebraic!
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\[\huge \frac{ \frac{ 4-2(2+2h) }{ 2+2h } }{h }\]
terenzreignz
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\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+2h}-2}{h}\]
is the same as
\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+2h}-\frac{2(2+2h)}{2+2h}}{h}\]
and further...
\[\huge \lim_{h \rightarrow 0}-\frac{\frac{4h}{2+2h}}{h}\]
terenzreignz
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Now reduce it to one fraction, and do any cancellations, if possible
burhan101
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why is it \[\frac{ 4x }{ 2+2h }\]
burhan101
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its supposed to be (2+h) *
terenzreignz
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Looked at your first post...
Ok, then
\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}-2}{h}\]\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}-\frac{2(2+h)}{2+h}}{h}\]
\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}-\frac{4+2h}{2+h}}{h}\]
mark_o.
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yup limit approaches to -2 as x approaches to zero
terenzreignz
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@mark_o. You might want to reconsider..., given that there was a correction; it's 2+h, not 2+2h as was in the first post.
burhan101
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sorry typing error :$
burhan101
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|dw:1350450481516:dw| why do i get this :S this doesnt make sense because that would mean the answer is zero
burhan101
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like what am i doing wrong?
terenzreignz
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You were to multiply
\[\frac{2+h}{2+h}\]
to the -2 in the numerator; not to the entire fraction.
terenzreignz
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that among other things... But yeah, multiply the
\[\frac{2+h}{2+h}\]
only to the -2, and redo your work...
burhan101
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but that doesnt get rid of the fraction
mark_o.
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hmm @terenzreignz, i didnt see the first posting of 2+h, i only saw 2+2h,, ththnx for reminding though...:D
terenzreignz
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We're not to get rid of it, only to make it simpler, ie, only one fraction bar.
burhan101
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|dw:1350450882525:dw| like that ?
terenzreignz
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That's right. Please continue.... :)
burhan101
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cross multiply?
burhan101
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nvm doesnt matter
terenzreignz
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Just distribute the 2.
burhan101
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|dw:1350451064789:dw|
terenzreignz
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ok... I think I know where you're getting at... Be careful, the way you wrote it is full of... difficulties.
On top, you should have 4 - (4 + 2h) Groupings can make a world of difference, so you better specify which operations are prioritised...
terenzreignz
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Not to mention you may have ignored and/or forgotten that there is another h in the denominator. Careful...
burhan101
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ohh alright !