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burhan101
 3 years ago
limit
burhan101
 3 years ago
limit

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burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{h \rightarrow 0}\frac{ \frac{ 4 }{ 2+2h }2 }{ h }\]

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350448824402:dw

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0maybe reducing it all to just one fraction might help

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350449555332:dw i know im doing something wrong

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.0find a CD in the numerator .

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge \frac{ \frac{ 42(2+2h) }{ 2+2h } }{h }\]

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+2h}2}{h}\] is the same as \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+2h}\frac{2(2+2h)}{2+2h}}{h}\] and further... \[\huge \lim_{h \rightarrow 0}\frac{\frac{4h}{2+2h}}{h}\]

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0Now reduce it to one fraction, and do any cancellations, if possible

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0why is it \[\frac{ 4x }{ 2+2h }\]

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0its supposed to be (2+h) *

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0Looked at your first post... Ok, then \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}2}{h}\]\[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}\frac{2(2+h)}{2+h}}{h}\] \[\huge \lim_{h \rightarrow 0}\frac{\frac{4}{2+h}\frac{4+2h}{2+h}}{h}\]

mark_o.
 3 years ago
Best ResponseYou've already chosen the best response.0yup limit approaches to 2 as x approaches to zero

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0@mark_o. You might want to reconsider..., given that there was a correction; it's 2+h, not 2+2h as was in the first post.

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0sorry typing error :$

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350450481516:dw why do i get this :S this doesnt make sense because that would mean the answer is zero

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0like what am i doing wrong?

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0You were to multiply \[\frac{2+h}{2+h}\] to the 2 in the numerator; not to the entire fraction.

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0that among other things... But yeah, multiply the \[\frac{2+h}{2+h}\] only to the 2, and redo your work...

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0but that doesnt get rid of the fraction

mark_o.
 3 years ago
Best ResponseYou've already chosen the best response.0hmm @terenzreignz, i didnt see the first posting of 2+h, i only saw 2+2h,, ththnx for reminding though...:D

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0We're not to get rid of it, only to make it simpler, ie, only one fraction bar.

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350450882525:dw like that ?

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0That's right. Please continue.... :)

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0Just distribute the 2.

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350451064789:dw

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0ok... I think I know where you're getting at... Be careful, the way you wrote it is full of... difficulties. On top, you should have 4  (4 + 2h) Groupings can make a world of difference, so you better specify which operations are prioritised...

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.0Not to mention you may have ignored and/or forgotten that there is another h in the denominator. Careful...
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