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3psilon

  • 3 years ago

Standard form for a parabola with this equation! Help please!

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  1. 3psilon
    • 3 years ago
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    \[y = -\frac{ 1 }{ 4 }x^{2} -x + \frac{ 1 }{ 4 } \]

  2. 3psilon
    • 3 years ago
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    I don't get the completing the square part

  3. Shadowys
    • 3 years ago
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    drawing? can't see equation

  4. hartnn
    • 3 years ago
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    that equation is in standard form, u need to get it in vertex form ?

  5. 3psilon
    • 3 years ago
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    yes

  6. hartnn
    • 3 years ago
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    -1/4(x^2+4x)+1/4 what to add and subtract ?

  7. 3psilon
    • 3 years ago
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    subtract 1/4

  8. hartnn
    • 3 years ago
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    we add and subtract the square of half of co-efficient of x so here, what is half of 4 ?

  9. 3psilon
    • 3 years ago
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    2

  10. hartnn
    • 3 years ago
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    and its square ?

  11. 3psilon
    • 3 years ago
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    4

  12. hartnn
    • 3 years ago
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    so what will u add and subtract ?

  13. 3psilon
    • 3 years ago
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    Do you subtract the square?

  14. hartnn
    • 3 years ago
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    u add and subtract the 4 like this: -1/4(x^2+4x+4 -4)+1/4 can u go ahead ?

  15. 3psilon
    • 3 years ago
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    y-1/4 +4 = -1/4(x^2+4x -4)

  16. hartnn
    • 3 years ago
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    y-1/4 -4(1/4) = -1/4(x^2+4x +4)

  17. 3psilon
    • 3 years ago
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    why -4(1/4) on the left???

  18. hartnn
    • 3 years ago
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    y=-1/4(x^2+4x+4 -4)+1/4 = -1/4 (x^2+4x+4) -1/4 (-4) +1/4 y-1/4 -1/4(4) = -1/4(x^2+4x+4) confusing ?

  19. 3psilon
    • 3 years ago
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    why did you not add it to both sides? why subtract? it says -1/4(-4)

  20. 3psilon
    • 3 years ago
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    Ohh I see it now

  21. 3psilon
    • 3 years ago
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    Wow thank you so much

  22. hartnn
    • 3 years ago
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    u can continue to get the vertex form, right ?

  23. 3psilon
    • 3 years ago
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    yess It is quite easy now. Thank you so much :) I can sleep now haha

  24. hartnn
    • 3 years ago
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    welcome ^_^

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