Standard form for a parabola with this equation! Help please!

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Standard form for a parabola with this equation! Help please!

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[y = -\frac{ 1 }{ 4 }x^{2} -x + \frac{ 1 }{ 4 } \]
I don't get the completing the square part
drawing? can't see equation

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Other answers:

that equation is in standard form, u need to get it in vertex form ?
yes
-1/4(x^2+4x)+1/4 what to add and subtract ?
subtract 1/4
we add and subtract the square of half of co-efficient of x so here, what is half of 4 ?
2
and its square ?
4
so what will u add and subtract ?
Do you subtract the square?
u add and subtract the 4 like this: -1/4(x^2+4x+4 -4)+1/4 can u go ahead ?
y-1/4 +4 = -1/4(x^2+4x -4)
y-1/4 -4(1/4) = -1/4(x^2+4x +4)
why -4(1/4) on the left???
y=-1/4(x^2+4x+4 -4)+1/4 = -1/4 (x^2+4x+4) -1/4 (-4) +1/4 y-1/4 -1/4(4) = -1/4(x^2+4x+4) confusing ?
why did you not add it to both sides? why subtract? it says -1/4(-4)
Ohh I see it now
Wow thank you so much
u can continue to get the vertex form, right ?
yess It is quite easy now. Thank you so much :) I can sleep now haha
welcome ^_^

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