3psilon
Standard form for a parabola with this equation! Help please!



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3psilon
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\[y = \frac{ 1 }{ 4 }x^{2} x + \frac{ 1 }{ 4 } \]

3psilon
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I don't get the completing the square part

Shadowys
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drawing? can't see equation

hartnn
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that equation is in standard form, u need to get it in vertex form ?

3psilon
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yes

hartnn
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1/4(x^2+4x)+1/4
what to add and subtract ?

3psilon
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subtract 1/4

hartnn
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we add and subtract the square of half of coefficient of x
so here, what is half of 4 ?

3psilon
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2

hartnn
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and its square ?

3psilon
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4

hartnn
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so what will u add and subtract ?

3psilon
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Do you subtract the square?

hartnn
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u add and subtract the 4
like this:
1/4(x^2+4x+4 4)+1/4
can u go ahead ?

3psilon
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y1/4 +4 = 1/4(x^2+4x 4)

hartnn
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y1/4 4(1/4) = 1/4(x^2+4x +4)

3psilon
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why 4(1/4) on the left???

hartnn
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y=1/4(x^2+4x+4 4)+1/4
= 1/4 (x^2+4x+4) 1/4 (4) +1/4
y1/4 1/4(4) = 1/4(x^2+4x+4)
confusing ?

3psilon
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why did you not add it to both sides? why subtract? it says 1/4(4)

3psilon
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Ohh I see it now

3psilon
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Wow thank you so much

hartnn
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u can continue to get the vertex form, right ?

3psilon
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yess
It is quite easy now. Thank you so much :) I can sleep now haha

hartnn
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welcome ^_^