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InsanelyChaotic
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Would anyone be so gracious as to helping me get a better understanding of the dreadful algebra!??!?!!? :)
Explain, in complete sentences, how you would use the elimination method to solve the following system of equations. Provide the solution to the system.
2x + 9y = 4
3x + 7y = 7
 2 years ago
 2 years ago
InsanelyChaotic Group Title
Would anyone be so gracious as to helping me get a better understanding of the dreadful algebra!??!?!!? :) Explain, in complete sentences, how you would use the elimination method to solve the following system of equations. Provide the solution to the system. 2x + 9y = 4 3x + 7y = 7
 2 years ago
 2 years ago

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Venomblast Group TitleBest ResponseYou've already chosen the best response.0
1st you want to figure out which variable you want to solve
 2 years ago

Venomblast Group TitleBest ResponseYou've already chosen the best response.0
ok. oh n btw i replied. the answer is A!!! fromt he previous question
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
thank you love!!!! :)))))))))))) I got that answer after I "closed" the question box
 2 years ago

Venomblast Group TitleBest ResponseYou've already chosen the best response.0
i said it 2 times. lol anywayz let do this problem
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
thank you nonetheless! ok let's go!
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Hey, an intermission, if you would oblige me... if x = y, then ax = ay right?
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
And if a = b and c = d then a + c = b + d Don't worry, these are relevant, we'll use them.
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
Thank you kind sir....! @terenzreignz
 2 years ago

Venomblast Group TitleBest ResponseYou've already chosen the best response.0
man i hate the ax=ay method
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
So you have 2x + 9y = 4 From our first rule, we can get 7(2x + 9y) = 7(4) 14x + 63y = 28, let's stop here, and call this "equation 1" You also have 3x + 7y = 7 Again, from our first rule, we can get 9(3x + 7y) = 9(7) 27x  63y = 63, stop here again, call this "equation 2" Are you getting it so far?
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
Yes, I've gone thru this a time before! But one question, how did you get the "7" in 7(2x+9y)
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
If you don't mind me asking.....! :))
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
Here's a joke: Subway called, they want their 6 inch back ;)
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
Another joke/flattery I made up: Verizon called, they want their "SMART" phone back
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Ok... You said you wanted to solve for x first (personally, I'd have gone for y first) So, we have to somehow get rid of the y. To do that, you have to make it so that the coefficient (the number that goes beside the letter) of the y in the first equation is equal to the NEGATIVE of the coefficient of the y in the second equation. In the first equation, the coeff of y was "9" and in the second, it was "7" You need to get what's called their "least common multiple" And that's 63. 63/9 is 7, so that's what I multiply to the first equation. 63/7 is 9, so that's what I multiply to the second equation, and then I NEGATED it (multiplied it by 1)
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
You'll see why this is done, when I proceed... shall I?
 2 years ago

Venomblast Group TitleBest ResponseYou've already chosen the best response.0
please do lol
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
oh my god....this is actually making sense!!!!! :')
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Remember our second rule? if a=b and c=d then a+c = b+d ? We'll just apply that, on a larger scale, sort of...
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I remember! I will, I promise!
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
All right, equation 1: 14x + 63y = 28 equation 2: 27x  63y = 63 Remember these?
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I do, yes
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Now we use the second rule, we add both expressions on the left, and equate them to the sum of the expressions on the right: 14x + 63y  27x  63y = 28 + 63
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
Notice something?
 2 years ago

Venomblast Group TitleBest ResponseYou've already chosen the best response.0
combine like term *cough**cough*
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I'm writing down the steps to refer to, but yes, I notice that in order to prolong the steps, I'll have to combine
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
and...?
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
Get x by itself
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
And then you'll have reduced it to a linear equation in one variable. Solve for x, and you're almost done! Just substitute that x which you get for the x in either one of the equations you started with, and then solve for y, and then you'll be done!
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
oh my....I appreciate your efforts!!
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.1
I appreciate your appreciation; have fun! :)
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
I will never have fun with math, but thank you:)
 2 years ago
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