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jazzylj Group Title

find the derivative of y with respect to x:

  • one year ago
  • one year ago

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  1. jazzylj Group Title
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    \[y=1/x(x+1)(x+2)\]

    • one year ago
  2. amorfide Group Title
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    |dw:1350454366994:dw| this?

    • one year ago
  3. jazzylj Group Title
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    sorry...1 is the numerator...everything else in the den.

    • one year ago
  4. amorfide Group Title
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    do you know the chain rule?

    • one year ago
  5. jazzylj Group Title
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    y=1/(x(x+1)(x+2))

    • one year ago
  6. jazzylj Group Title
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    I pretty much know nothing for my calc class. I just need to get through this assignment that's due tomorrow and then I start my sessions with my tutor...any help is greatly appreciated

    • one year ago
  7. Mimi_x3 Group Title
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    \[\large \frac{1}{x(x+1)(x+2)} \]

    • one year ago
  8. Mimi_x3 Group Title
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    well you can use the product rule or the quotient rule

    • one year ago
  9. Mimi_x3 Group Title
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    have you tried expanding it

    • one year ago
  10. jazzylj Group Title
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    So...1\[\frac{ 1 }{ x ^{3}+3x ^{2}+2x}?\]

    • one year ago
  11. amorfide Group Title
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    you could bring it to the top, so all the powers change signs to a negative

    • one year ago
  12. jazzylj Group Title
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    \[y'=\frac{ -(3x ^{2}+6x+2) }{ x ^{2}(x ^{2}+3x+2)^{2} }..???

    • one year ago
  13. jazzylj Group Title
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    sorry...that's so ugly. I'll retype it.

    • one year ago
  14. jazzylj Group Title
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    \[y'=\frac{ -(3x ^{2}+6x+2) }{ x ^{2}(x ^{2}+3x+2)^{2} }\]

    • one year ago
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