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jazzylj

  • 3 years ago

find the derivative of y with respect to x:

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  1. jazzylj
    • 3 years ago
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    \[y=1/x(x+1)(x+2)\]

  2. amorfide
    • 3 years ago
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    |dw:1350454366994:dw| this?

  3. jazzylj
    • 3 years ago
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    sorry...1 is the numerator...everything else in the den.

  4. amorfide
    • 3 years ago
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    do you know the chain rule?

  5. jazzylj
    • 3 years ago
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    y=1/(x(x+1)(x+2))

  6. jazzylj
    • 3 years ago
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    I pretty much know nothing for my calc class. I just need to get through this assignment that's due tomorrow and then I start my sessions with my tutor...any help is greatly appreciated

  7. Mimi_x3
    • 3 years ago
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    \[\large \frac{1}{x(x+1)(x+2)} \]

  8. Mimi_x3
    • 3 years ago
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    well you can use the product rule or the quotient rule

  9. Mimi_x3
    • 3 years ago
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    have you tried expanding it

  10. jazzylj
    • 3 years ago
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    So...1\[\frac{ 1 }{ x ^{3}+3x ^{2}+2x}?\]

  11. amorfide
    • 3 years ago
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    you could bring it to the top, so all the powers change signs to a negative

  12. jazzylj
    • 3 years ago
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    \[y'=\frac{ -(3x ^{2}+6x+2) }{ x ^{2}(x ^{2}+3x+2)^{2} }..???

  13. jazzylj
    • 3 years ago
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    sorry...that's so ugly. I'll retype it.

  14. jazzylj
    • 3 years ago
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    \[y'=\frac{ -(3x ^{2}+6x+2) }{ x ^{2}(x ^{2}+3x+2)^{2} }\]

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