jazzylj
find the derivative of y with respect to x:
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jazzylj
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\[y=1/x(x+1)(x+2)\]
amorfide
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|dw:1350454366994:dw|
this?
jazzylj
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sorry...1 is the numerator...everything else in the den.
amorfide
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do you know the chain rule?
jazzylj
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y=1/(x(x+1)(x+2))
jazzylj
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I pretty much know nothing for my calc class. I just need to get through this assignment that's due tomorrow and then I start my sessions with my tutor...any help is greatly appreciated
Mimi_x3
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\[\large \frac{1}{x(x+1)(x+2)} \]
Mimi_x3
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well you can use the product rule or the quotient rule
Mimi_x3
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have you tried expanding it
jazzylj
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So...1\[\frac{ 1 }{ x ^{3}+3x ^{2}+2x}?\]
amorfide
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you could bring it to the top, so all the powers change signs to a negative
jazzylj
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\[y'=\frac{ -(3x ^{2}+6x+2) }{ x ^{2}(x ^{2}+3x+2)^{2} }..???
jazzylj
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sorry...that's so ugly. I'll retype it.
jazzylj
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\[y'=\frac{ -(3x ^{2}+6x+2) }{ x ^{2}(x ^{2}+3x+2)^{2} }\]