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Find the derivative of f(x) =2x^2-1/x^2 in three ways : (a) using the quotient rule (b) using the product rule (c) using neither the product rule nor the quotient rule I have already done all of these out. my answers: a) 2/x^3 b)-4x^3+x+8/2 c)2 for each one I've gotten a different answer, just wondering why. I think I'm supposed to get the same answer each time.

Mathematics
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is it:\[\frac{2x^2-1}{x^2}\]?
yes it is.
Messed up in product rule somewhere.

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Other answers:

Maybe double-check your exponents.
uhm.
:)
For product rule start with f(x) = (2x^2-1)(x^-2) Then it's 'first times the derivative of the second, plus the second times the derivative of the first.'
i know the formula.
non-quotient-or-product-rule way would be: 2x^2/x^2 - 1/x^2 =2 -1/x^2 (2 -1/x^2)' = - (-2*x^-3)
now i re-did it and got 2/x
for the third way i did the definition of the derivative and i only got a 2
You're losing track of an exponent somewhere. What are you getting for the derivative of x^-2 ?
i re-did the product rule and got 2/x
ur doing it wrong.
okay i got a and b right now, just wondering why my definition of the derivative one is wrong.
i got 2/x^3 for a and b but only 2 for the definition of the derivative.

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