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dealing with parametric curves
if dy/dx = dy/dt/dx/dt = sin(t)/2sin(2t)
now I need to find d^2y/dx^2 and i'm a bit stuck...
 one year ago
 one year ago
dealing with parametric curves if dy/dx = dy/dt/dx/dt = sin(t)/2sin(2t) now I need to find d^2y/dx^2 and i'm a bit stuck...
 one year ago
 one year ago

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TuringTestBest ResponseYou've already chosen the best response.2
\[\frac{d^2y}{dx^2}=\Large{\frac{d}{dt}\left(\frac{dy}{dx}\right)\over\frac{dx}{dt}}\]
 one year ago

vanhoeak2Best ResponseYou've already chosen the best response.0
\[\frac{ \frac{ d }{ dt }(\frac{ \sin(t) }{ 2\sin(2t) }) }{ 2\sin(2t) }\] then I would have\[\frac{ \frac{ \cos (t) }{ 4\cos(2t)} }{ 2\sin(2t) }\] is that correct?
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
\[\frac d{dt}(\frac{\sin t}{2\sin 2t})\neq\frac{\cos t}{4\cos t}\]remember the quotient rule...
 one year ago

TuringTestBest ResponseYou've already chosen the best response.2
you may do well to simplify first\[\frac{\sin t}{2\sin(2t)}=\frac{\sin t}{4\sin t\cos t}=\frac1{4\cos t}=\frac14\sec t\]
 one year ago

vanhoeak2Best ResponseYou've already chosen the best response.0
that makes more sense
 one year ago
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