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Suppose a parabola has an axis of symmetry at x = –7, a maximum height of 4, and also passes through the point (–6, 0). Write the equation of the parabola in vertex form.
 one year ago
 one year ago
Suppose a parabola has an axis of symmetry at x = –7, a maximum height of 4, and also passes through the point (–6, 0). Write the equation of the parabola in vertex form.
 one year ago
 one year ago

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tcarroll010Best ResponseYou've already chosen the best response.0
Since you have an axis of symmetry at x = 7 and a maximum height of 4, you have the additional point of (7,4) for the parabola. From symmetry, you have point (8,0). If you use y = ax^2 + bx + c, you can set up 3 linear equations in 3 unknowns and solve for a, b, and c.
 one year ago

meg_pooBest ResponseYou've already chosen the best response.0
so like this would be the vertex equation y=4x^256x192
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.0
You have the point (6,0) from your problem statement plus the 2 points I gave you for 3 points total. Now that you have 3 points, and since they are not collinear (all on the same line), they uniquely determine a polynomial of degree 2, which is a parabola. If you use the equation I gave you and set up 3 substitutions, you will have 3 equations in the unknowns of a, b, and c. So you just have to solve a linear system. Once you get to that point with these 3 points, it's a piece of cake.
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.0
Yes, that would be the form, but first you have to solve for a, b, and c from the method I outlined.
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.0
Yes, you've got it now.
 one year ago
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