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Kamille

  • 2 years ago

I need to find x: (a+x)/(b-x)=(4a)/(3b) Anyone has any ideas?

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  1. Kamille
    • 2 years ago
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    Also, I know that \[b \neq 0 \] and \[b \neq x\]

  2. Kamille
    • 2 years ago
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    \[(\frac{ a+x }{ b-x } )=\frac{ 4a }{ 3b }\]

  3. kropot72
    • 2 years ago
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    First multiply both sides by (b - x) to eliminate the fraction of the left hand side. Then multiply both sides of the result by 3b to eliminate the fraction on the right hand side. Can you do that?

  4. Kamille
    • 2 years ago
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    Well, I get this. If you have time, can you look? (a+x)/(b-x)=(4a/3b)|*(b-x) a+x=4a/3b(b-x)|*3b 3ba+3bx=4a/b-x

  5. Kamille
    • 2 years ago
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    If you wont understand what I get, i can use "equation" to show.

  6. kropot72
    • 2 years ago
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    Multiplying both sides by (b - x) gives: \[\frac{a+x}{b-x}\times (b-x)=\frac{4a(b-x)}{3b}\] \[a+x=\frac{4a(b-x)}{3b}\] Now multiplying both sides by 3b gives: \[3b(a+x)=4a(b-x)\] Do you follow so far?

  7. Kamille
    • 2 years ago
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    Well, I understand this. What to do next?

  8. kropot72
    • 2 years ago
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    Next multiply out to remove the brackets, then rearrange to get the two terms in x on the left hand side.

  9. kropot72
    • 2 years ago
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    Finally you factorise out x and perform a division to get: \[x=\frac{?}{?}\]

  10. Kamille
    • 2 years ago
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    Oh,thank you very much. 3ba+3bx=4ab-4ax 3bx=4ab-3ab-4ax 3bx+4ax=ab x(3b+4a)=ab x=ab/3b+4a correct?

  11. kropot72
    • 2 years ago
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    Good work! Your answer is correct :)

  12. Kamille
    • 2 years ago
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    Thank you very much:))

  13. kropot72
    • 2 years ago
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    You're welcome :)

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