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Kamille Group Title

I need to find x: (a+x)/(b-x)=(4a)/(3b) Anyone has any ideas?

  • 2 years ago
  • 2 years ago

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  1. Kamille Group Title
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    Also, I know that \[b \neq 0 \] and \[b \neq x\]

    • 2 years ago
  2. Kamille Group Title
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    \[(\frac{ a+x }{ b-x } )=\frac{ 4a }{ 3b }\]

    • 2 years ago
  3. kropot72 Group Title
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    First multiply both sides by (b - x) to eliminate the fraction of the left hand side. Then multiply both sides of the result by 3b to eliminate the fraction on the right hand side. Can you do that?

    • 2 years ago
  4. Kamille Group Title
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    Well, I get this. If you have time, can you look? (a+x)/(b-x)=(4a/3b)|*(b-x) a+x=4a/3b(b-x)|*3b 3ba+3bx=4a/b-x

    • 2 years ago
  5. Kamille Group Title
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    If you wont understand what I get, i can use "equation" to show.

    • 2 years ago
  6. kropot72 Group Title
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    Multiplying both sides by (b - x) gives: \[\frac{a+x}{b-x}\times (b-x)=\frac{4a(b-x)}{3b}\] \[a+x=\frac{4a(b-x)}{3b}\] Now multiplying both sides by 3b gives: \[3b(a+x)=4a(b-x)\] Do you follow so far?

    • 2 years ago
  7. Kamille Group Title
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    Well, I understand this. What to do next?

    • 2 years ago
  8. kropot72 Group Title
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    Next multiply out to remove the brackets, then rearrange to get the two terms in x on the left hand side.

    • 2 years ago
  9. kropot72 Group Title
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    Finally you factorise out x and perform a division to get: \[x=\frac{?}{?}\]

    • 2 years ago
  10. Kamille Group Title
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    Oh,thank you very much. 3ba+3bx=4ab-4ax 3bx=4ab-3ab-4ax 3bx+4ax=ab x(3b+4a)=ab x=ab/3b+4a correct?

    • 2 years ago
  11. kropot72 Group Title
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    Good work! Your answer is correct :)

    • 2 years ago
  12. Kamille Group Title
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    Thank you very much:))

    • 2 years ago
  13. kropot72 Group Title
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    You're welcome :)

    • 2 years ago
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