## Kamille Group Title I need to find x: (a+x)/(b-x)=(4a)/(3b) Anyone has any ideas? one year ago one year ago

1. Kamille Group Title

Also, I know that $b \neq 0$ and $b \neq x$

2. Kamille Group Title

$(\frac{ a+x }{ b-x } )=\frac{ 4a }{ 3b }$

3. kropot72 Group Title

First multiply both sides by (b - x) to eliminate the fraction of the left hand side. Then multiply both sides of the result by 3b to eliminate the fraction on the right hand side. Can you do that?

4. Kamille Group Title

Well, I get this. If you have time, can you look? (a+x)/(b-x)=(4a/3b)|*(b-x) a+x=4a/3b(b-x)|*3b 3ba+3bx=4a/b-x

5. Kamille Group Title

If you wont understand what I get, i can use "equation" to show.

6. kropot72 Group Title

Multiplying both sides by (b - x) gives: $\frac{a+x}{b-x}\times (b-x)=\frac{4a(b-x)}{3b}$ $a+x=\frac{4a(b-x)}{3b}$ Now multiplying both sides by 3b gives: $3b(a+x)=4a(b-x)$ Do you follow so far?

7. Kamille Group Title

Well, I understand this. What to do next?

8. kropot72 Group Title

Next multiply out to remove the brackets, then rearrange to get the two terms in x on the left hand side.

9. kropot72 Group Title

Finally you factorise out x and perform a division to get: $x=\frac{?}{?}$

10. Kamille Group Title

Oh,thank you very much. 3ba+3bx=4ab-4ax 3bx=4ab-3ab-4ax 3bx+4ax=ab x(3b+4a)=ab x=ab/3b+4a correct?

11. kropot72 Group Title