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I need to find x: (a+x)/(b-x)=(4a)/(3b) Anyone has any ideas?

Mathematics
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Also, I know that \[b \neq 0 \] and \[b \neq x\]
\[(\frac{ a+x }{ b-x } )=\frac{ 4a }{ 3b }\]
First multiply both sides by (b - x) to eliminate the fraction of the left hand side. Then multiply both sides of the result by 3b to eliminate the fraction on the right hand side. Can you do that?

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Other answers:

Well, I get this. If you have time, can you look? (a+x)/(b-x)=(4a/3b)|*(b-x) a+x=4a/3b(b-x)|*3b 3ba+3bx=4a/b-x
If you wont understand what I get, i can use "equation" to show.
Multiplying both sides by (b - x) gives: \[\frac{a+x}{b-x}\times (b-x)=\frac{4a(b-x)}{3b}\] \[a+x=\frac{4a(b-x)}{3b}\] Now multiplying both sides by 3b gives: \[3b(a+x)=4a(b-x)\] Do you follow so far?
Well, I understand this. What to do next?
Next multiply out to remove the brackets, then rearrange to get the two terms in x on the left hand side.
Finally you factorise out x and perform a division to get: \[x=\frac{?}{?}\]
Oh,thank you very much. 3ba+3bx=4ab-4ax 3bx=4ab-3ab-4ax 3bx+4ax=ab x(3b+4a)=ab x=ab/3b+4a correct?
Good work! Your answer is correct :)
Thank you very much:))
You're welcome :)

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