## SmithAshley Group Title Solve. 3t < –15 (1 point) t < –5 t > –5 t < –45 t > –45 one year ago one year ago

1. santw Group Title

divide each side by 3. t < -5

2. SmithAshley Group Title

can you help me with a couple more?

3. santw Group Title

sure!

4. SmithAshley Group Title

Solve. ≥ 12 (1 point) r ≤ 48 r ≥ 3 r ≥ 48 r ≤ 3

5. SmithAshley Group Title

@santw

6. santw Group Title

did you type that right? @SmithAshley

7. SmithAshley Group Title

Solve. r/4 ≥ 12 (1 point)r ≤ 48 r ≥ 3 r ≥ 48 r ≤ 3

8. santw Group Title

to get rid of the /4, multiply both sides by 4. after that you have $4(\frac{r }{ 4 } \ge 12)$ the 4's cancel and leaves the 3rd option. $r \ge48$

9. santw Group Title

i'm trying to make sure you get the work too!

10. SmithAshley Group Title

can you help me with one more please?

11. santw Group Title

not the third, the second! ~_~ just post em, and notify me.

12. SmithAshley Group Title

Solve. –3y ≤ –18 (1 point) y ≤ –6 y ≤ 6 y ≥ 6 y ≤ 54 @santw

13. santw Group Title

divide each side by -3. so you get $y \le6$

14. SmithAshley Group Title

You only got 1 right and the other wrong :( @santw

15. santw Group Title

sorry! which one?

16. SmithAshley Group Title

number 2 and 3. Thats ok! :)

17. Elaine16 Group Title

3t < -15 t < -5 is right r/4>= 12 r >= 48 is also right -3y=< -18 however isn't y=< 6 because when you divide by a negative number you have to switch the sign around to make it y>= 6. Just for anyone finding this who may be confused by "SmithAshley" saying 2 were wrong when in fact only one was wrong.