Solve. 3t < –15 (1 point) t < –5 t > –5 t < –45 t > –45

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Solve. 3t < –15 (1 point) t < –5 t > –5 t < –45 t > –45

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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divide each side by 3. t < -5
can you help me with a couple more?
sure!

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Solve. ≥ 12 (1 point) r ≤ 48 r ≥ 3 r ≥ 48 r ≤ 3
did you type that right? @SmithAshley
Solve. r/4 ≥ 12 (1 point)r ≤ 48 r ≥ 3 r ≥ 48 r ≤ 3
to get rid of the /4, multiply both sides by 4. after that you have \[4(\frac{r }{ 4 } \ge 12)\] the 4's cancel and leaves the 3rd option. \[r \ge48\]
i'm trying to make sure you get the work too!
can you help me with one more please?
not the third, the second! ~_~ just post em, and notify me.
Solve. –3y ≤ –18 (1 point) y ≤ –6 y ≤ 6 y ≥ 6 y ≤ 54 @santw
divide each side by -3. so you get \[y \le6\]
You only got 1 right and the other wrong :( @santw
sorry! which one?
number 2 and 3. Thats ok! :)
3t < -15 t < -5 is right r/4>= 12 r >= 48 is also right -3y=< -18 however isn't y=< 6 because when you divide by a negative number you have to switch the sign around to make it y>= 6. Just for anyone finding this who may be confused by "SmithAshley" saying 2 were wrong when in fact only one was wrong.

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