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SmithAshley

Solve. 3t < –15 (1 point) t < –5 t > –5 t < –45 t > –45

  • one year ago
  • one year ago

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  1. santw
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    divide each side by 3. t < -5

    • one year ago
  2. SmithAshley
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    can you help me with a couple more?

    • one year ago
  3. santw
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    sure!

    • one year ago
  4. SmithAshley
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    Solve. ≥ 12 (1 point) r ≤ 48 r ≥ 3 r ≥ 48 r ≤ 3

    • one year ago
  5. SmithAshley
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    @santw

    • one year ago
  6. santw
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    did you type that right? @SmithAshley

    • one year ago
  7. SmithAshley
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    Solve. r/4 ≥ 12 (1 point)r ≤ 48 r ≥ 3 r ≥ 48 r ≤ 3

    • one year ago
  8. santw
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    to get rid of the /4, multiply both sides by 4. after that you have \[4(\frac{r }{ 4 } \ge 12)\] the 4's cancel and leaves the 3rd option. \[r \ge48\]

    • one year ago
  9. santw
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    i'm trying to make sure you get the work too!

    • one year ago
  10. SmithAshley
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    can you help me with one more please?

    • one year ago
  11. santw
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    not the third, the second! ~_~ just post em, and notify me.

    • one year ago
  12. SmithAshley
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    Solve. –3y ≤ –18 (1 point) y ≤ –6 y ≤ 6 y ≥ 6 y ≤ 54 @santw

    • one year ago
  13. santw
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    divide each side by -3. so you get \[y \le6\]

    • one year ago
  14. SmithAshley
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    You only got 1 right and the other wrong :( @santw

    • one year ago
  15. santw
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    sorry! which one?

    • one year ago
  16. SmithAshley
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    number 2 and 3. Thats ok! :)

    • one year ago
  17. Elaine16
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    3t < -15 t < -5 is right r/4>= 12 r >= 48 is also right -3y=< -18 however isn't y=< 6 because when you divide by a negative number you have to switch the sign around to make it y>= 6. Just for anyone finding this who may be confused by "SmithAshley" saying 2 were wrong when in fact only one was wrong.

    • 4 months ago
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