SmithAshley
Solve. 3t < –15 (1 point)
t < –5
t > –5
t < –45
t > –45
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santw
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divide each side by 3.
t < -5
SmithAshley
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can you help me with a couple more?
santw
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sure!
SmithAshley
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Solve. ≥ 12 (1 point)
r ≤ 48
r ≥ 3
r ≥ 48
r ≤ 3
SmithAshley
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@santw
santw
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did you type that right? @SmithAshley
SmithAshley
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Solve. r/4 ≥ 12 (1 point)r ≤ 48
r ≥ 3
r ≥ 48
r ≤ 3
santw
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to get rid of the /4, multiply both sides by 4.
after that you have \[4(\frac{r }{ 4 } \ge 12)\]
the 4's cancel and leaves the 3rd option.
\[r \ge48\]
santw
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i'm trying to make sure you get the work too!
SmithAshley
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can you help me with one more please?
santw
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not the third, the second! ~_~
just post em, and notify me.
SmithAshley
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Solve. –3y ≤ –18 (1 point)
y ≤ –6
y ≤ 6
y ≥ 6
y ≤ 54
@santw
santw
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divide each side by -3.
so you get \[y \le6\]
SmithAshley
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You only got 1 right and the other wrong :( @santw
santw
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sorry! which one?
SmithAshley
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number 2 and 3. Thats ok! :)
Elaine16
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3t < -15
t < -5 is right
r/4>= 12
r >= 48 is also right
-3y=< -18 however isn't y=< 6 because when you divide by a negative number you have to switch the sign around to make it y>= 6.
Just for anyone finding this who may be confused by "SmithAshley" saying 2 were wrong when in fact only one was wrong.