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bilgads Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{ }^{} \frac{ x1 }{x ^{2}4x+5 } \]
 2 years ago

bilgads Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 1 }{2 } \int\limits_{}^{} \frac{ 2x4+2 }{ x^{2}4x+5 } \]
 2 years ago

bilgads Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 1 }{ 2 } \int\limits_{}^{} \left[ \int\limits_{}^{} \frac{ 2x4 }{ x ^{2}4x+5 } dx + \int\limits_{}^{} \frac{ 2 }{ x ^{2}4x+5 }dx\right] \]
 2 years ago

bilgads Group TitleBest ResponseYou've already chosen the best response.0
sorry we have not integral side \[\frac{ 1 }{ 2 }\]
 2 years ago

bilgads Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 1 }{ 2 } \left[ \ln (x ^{2}4x+5) + 2\int\limits_{}^{}\frac{ 1 }{ x ^{2} 4x+5 } dx\right]\]
 2 years ago

bilgads Group TitleBest ResponseYou've already chosen the best response.0
we have \[\int\limits_{}^{} \frac{ 1 }{ (x2)^{2} +1}dx = \tan^{1} (x2)\]
 2 years ago

bilgads Group TitleBest ResponseYou've already chosen the best response.0
so the integral is \[\frac{ 1 }{ 2 }\ln (x ^{2}4x+5) + \tan^{1} (x2) +C\]
 2 years ago

adi171 Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits x1\div x ^{2}4x + 4 +4 8 +5\]
 one year ago

adi171 Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits \frac{ x1 }{ (x2)^2 +1 }\]
 one year ago

adi171 Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits \frac{ x }{ (x2)^2 +1 }dx  \int\limits \frac{ 1 }{ (x2)^2 +1 } dx\]
 one year ago

adi171 Group TitleBest ResponseYou've already chosen the best response.0
\[\ln (x^2 4x +5)  \tan^{1} (x2) +C\]
 one year ago

adi171 Group TitleBest ResponseYou've already chosen the best response.0
this is the right ans....when u have a quadratic eq. in denominator remember to add and subtract b^2/2a.....and then make quadratic + constant form eq.
 one year ago
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