## sara1234 Group Title dont understand this assigment one year ago one year ago

1. sara1234 Group Title

2. satellite73 Group Title

jeez that's a killer maybe we can do a couple of them

3. drpruitt Group Title

You are breaking down the sin function into words. Start with the Amplitude and work your way down

4. satellite73 Group Title

because $$\sin(\theta)$$ is the second coordinate of a point on the unit circle, whose equation is $$x^2+y^2=1$$ you know the range of sine is $$[-1,1]$$ since the lowest point on the circle is $$(0,-1)$$ and the highest point is $$(0,1)$$

5. satellite73 Group Title

this also makes the "amplitude" one since it is the highest the sine function can go

6. satellite73 Group Title

because one you traverse around the unit circle one rotation, you are right back where you started from, and because we know the unit circle has circumference $$2\pi$$ we see that $$\sin(\theta)=\sin(\theta +2\pi)$$ making sine a periodic function with period $$2\pi$$

7. satellite73 Group Title

first off, do you know how sine relates to the unit circle?

8. sara1234 Group Title

no

9. satellite73 Group Title

ahh ok then that is where we need to start. so you know how to find the sine of any number for example $\sin(\frac{\pi}{2})$?

10. satellite73 Group Title

you do it by finding the second coordinate of the point on the unit circle corresponding to the angle

11. satellite73 Group Title

ok it is here lets take it step by step