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sara1234

  • 2 years ago

dont understand this assigment

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  1. sara1234
    • 2 years ago
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  2. satellite73
    • 2 years ago
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    jeez that's a killer maybe we can do a couple of them

  3. drpruitt
    • 2 years ago
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    You are breaking down the sin function into words. Start with the Amplitude and work your way down

  4. satellite73
    • 2 years ago
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    because \(\sin(\theta)\) is the second coordinate of a point on the unit circle, whose equation is \(x^2+y^2=1\) you know the range of sine is \([-1,1]\) since the lowest point on the circle is \((0,-1)\) and the highest point is \((0,1)\)

  5. satellite73
    • 2 years ago
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    this also makes the "amplitude" one since it is the highest the sine function can go

  6. satellite73
    • 2 years ago
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    because one you traverse around the unit circle one rotation, you are right back where you started from, and because we know the unit circle has circumference \(2\pi\) we see that \(\sin(\theta)=\sin(\theta +2\pi)\) making sine a periodic function with period \(2\pi\)

  7. satellite73
    • 2 years ago
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    first off, do you know how sine relates to the unit circle?

  8. sara1234
    • 2 years ago
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    no

  9. satellite73
    • 2 years ago
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    ahh ok then that is where we need to start. so you know how to find the sine of any number for example \[\sin(\frac{\pi}{2})\]?

  10. satellite73
    • 2 years ago
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    you do it by finding the second coordinate of the point on the unit circle corresponding to the angle

  11. satellite73
    • 2 years ago
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    ok it is here lets take it step by step

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