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anonymous
 3 years ago
dont understand this assigment
anonymous
 3 years ago
dont understand this assigment

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0jeez that's a killer maybe we can do a couple of them

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You are breaking down the sin function into words. Start with the Amplitude and work your way down

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because \(\sin(\theta)\) is the second coordinate of a point on the unit circle, whose equation is \(x^2+y^2=1\) you know the range of sine is \([1,1]\) since the lowest point on the circle is \((0,1)\) and the highest point is \((0,1)\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this also makes the "amplitude" one since it is the highest the sine function can go

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because one you traverse around the unit circle one rotation, you are right back where you started from, and because we know the unit circle has circumference \(2\pi\) we see that \(\sin(\theta)=\sin(\theta +2\pi)\) making sine a periodic function with period \(2\pi\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0first off, do you know how sine relates to the unit circle?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ahh ok then that is where we need to start. so you know how to find the sine of any number for example \[\sin(\frac{\pi}{2})\]?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you do it by finding the second coordinate of the point on the unit circle corresponding to the angle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok it is here lets take it step by step
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