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satellite73Best ResponseYou've already chosen the best response.1
jeez that's a killer maybe we can do a couple of them
 one year ago

drpruittBest ResponseYou've already chosen the best response.0
You are breaking down the sin function into words. Start with the Amplitude and work your way down
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
because \(\sin(\theta)\) is the second coordinate of a point on the unit circle, whose equation is \(x^2+y^2=1\) you know the range of sine is \([1,1]\) since the lowest point on the circle is \((0,1)\) and the highest point is \((0,1)\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
this also makes the "amplitude" one since it is the highest the sine function can go
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
because one you traverse around the unit circle one rotation, you are right back where you started from, and because we know the unit circle has circumference \(2\pi\) we see that \(\sin(\theta)=\sin(\theta +2\pi)\) making sine a periodic function with period \(2\pi\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
first off, do you know how sine relates to the unit circle?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
ahh ok then that is where we need to start. so you know how to find the sine of any number for example \[\sin(\frac{\pi}{2})\]?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
you do it by finding the second coordinate of the point on the unit circle corresponding to the angle
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
ok it is here lets take it step by step
 one year ago
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