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sara1234

dont understand this assigment

  • one year ago
  • one year ago

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  1. sara1234
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    • one year ago
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  2. satellite73
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    jeez that's a killer maybe we can do a couple of them

    • one year ago
  3. drpruitt
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    You are breaking down the sin function into words. Start with the Amplitude and work your way down

    • one year ago
  4. satellite73
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    because \(\sin(\theta)\) is the second coordinate of a point on the unit circle, whose equation is \(x^2+y^2=1\) you know the range of sine is \([-1,1]\) since the lowest point on the circle is \((0,-1)\) and the highest point is \((0,1)\)

    • one year ago
  5. satellite73
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    this also makes the "amplitude" one since it is the highest the sine function can go

    • one year ago
  6. satellite73
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    because one you traverse around the unit circle one rotation, you are right back where you started from, and because we know the unit circle has circumference \(2\pi\) we see that \(\sin(\theta)=\sin(\theta +2\pi)\) making sine a periodic function with period \(2\pi\)

    • one year ago
  7. satellite73
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    first off, do you know how sine relates to the unit circle?

    • one year ago
  8. sara1234
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    no

    • one year ago
  9. satellite73
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    ahh ok then that is where we need to start. so you know how to find the sine of any number for example \[\sin(\frac{\pi}{2})\]?

    • one year ago
  10. satellite73
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    you do it by finding the second coordinate of the point on the unit circle corresponding to the angle

    • one year ago
  11. satellite73
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    ok it is here lets take it step by step

    • one year ago
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