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sara1234 Group Title

dont understand this assigment

  • 2 years ago
  • 2 years ago

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  1. sara1234 Group Title
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    • 2 years ago
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  2. satellite73 Group Title
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    jeez that's a killer maybe we can do a couple of them

    • 2 years ago
  3. drpruitt Group Title
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    You are breaking down the sin function into words. Start with the Amplitude and work your way down

    • 2 years ago
  4. satellite73 Group Title
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    because \(\sin(\theta)\) is the second coordinate of a point on the unit circle, whose equation is \(x^2+y^2=1\) you know the range of sine is \([-1,1]\) since the lowest point on the circle is \((0,-1)\) and the highest point is \((0,1)\)

    • 2 years ago
  5. satellite73 Group Title
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    this also makes the "amplitude" one since it is the highest the sine function can go

    • 2 years ago
  6. satellite73 Group Title
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    because one you traverse around the unit circle one rotation, you are right back where you started from, and because we know the unit circle has circumference \(2\pi\) we see that \(\sin(\theta)=\sin(\theta +2\pi)\) making sine a periodic function with period \(2\pi\)

    • 2 years ago
  7. satellite73 Group Title
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    first off, do you know how sine relates to the unit circle?

    • 2 years ago
  8. sara1234 Group Title
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    no

    • 2 years ago
  9. satellite73 Group Title
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    ahh ok then that is where we need to start. so you know how to find the sine of any number for example \[\sin(\frac{\pi}{2})\]?

    • 2 years ago
  10. satellite73 Group Title
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    you do it by finding the second coordinate of the point on the unit circle corresponding to the angle

    • 2 years ago
  11. satellite73 Group Title
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    ok it is here lets take it step by step

    • 2 years ago
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