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Can you see the picture?

"From top to bottom the whole target stand is supposed to be 1.5 meters."
where does it say that??

then it's easy to solve.

Haha, that might be a necessary piece of information! It makes point A known! :)

Oh good it can be solved :D

IS 1.1 the height of A?

OS crashed the pdf page... what were the measurements...

1.5 - the distance from the top... whatever it was something like 4cm * 4 + 8cm?

The height was 1.5m, and the point was 24 cm down.

.24m down.

ah ok so (18, 1.26) is the second point...

Do I put the points into the quadratic equation form?

When I was working on this earlier I put c as being 1.39 for one of the equations.

1.26 = a(18)^2 +b18 +1.39
0 = a(45)^2 +b(45) +1.39

a is obviously going to be negative..

Do i solve it like linear systems?

yep

Can I work this out and you guys tell me if i did it right?

sure

Ok, thank you I'll get working on it.

no.

What should I do instead?

I solved
-.13 = 18^2a +18b
for b and subsed in to the other equation
a~ -8.765E-4
b~ .008555

To find the maximum height do I use the formula -b/2a?

What's the equation for height. Oh and with the number for a should i type e-4 in my calculator?

10^-4

we just found the equation for height...

We use the second equation?

the vertex is the location of the max height

|dw:1350531626084:dw|

Does that mean the y-coordinate of the vertex is the max height?

(x,y) = (x location of max height, max height)

yes

Do i already know the vertex? Was it one of the points from earlier?

yeah it was (45,0)

you already knew the answer before you did the problem, so this was all a huge waste of time.

I still don't get how to arrive to the answer and I need to show the work

find a and b
y= ax^2 +bx +c
find the vertex

If the vertex is supposed to be (45,0) wouldn't that make the maximum height 0? o_o

When I try to find the height I get -4.88025002715, but I know that can't be write.

it's not.

plug x =-b/2a into the equation of the parabola

The ax^2+bx+c type equation?

alternately, calculate (4ac -b^2) / 4a
your choice.

Ok I'll try that

I got 1.3691, but I probably miscalculated somewhere unless I'm supposed to round it to 1.4

it's 1.41

1.410876 using the rough values for a and b that I gave