A community for students.
Here's the question you clicked on:
 0 viewing
ConDawg
 2 years ago
Evaluate the following limit. If the answer is positive infinite, type "I"; if negative infinite, type "N"; and if it does not exist, type "D".
lim > 4/9x+3
x goes to infinity
ConDawg
 2 years ago
Evaluate the following limit. If the answer is positive infinite, type "I"; if negative infinite, type "N"; and if it does not exist, type "D". lim > 4/9x+3 x goes to infinity

This Question is Closed

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.1Is it \[\lim_{x \rightarrow \infty} \frac{4}{9x+3}\] for your question?

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0yes sorry!! I was busy doing other practice questions for my test tomorrow.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.1Never mind :) 1. Divide both numerator and denominator by x, what do you get?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.1Yup! Now, you need to know that \[\lim_{x \rightarrow \infty}\frac{1}{x} = 0\]Now, can you evaluate the limit?

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0what does the 1/x = 0 mean? does that also mean that 4/x  0?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.1It's \[\lim_{x \rightarrow \infty \frac{1}{x}} = 0\] Imagine 1 is divided by a very large number, then you probably get 0.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.1Aww.. Bad typing! It's \[\lim_{x \rightarrow \infty} \frac{1}{x}=0\]

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0so 4 divide by a very large number is pretty much 0, so I think the answer should be 0/9.

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0:) Thank you! It's greatly appreciated!

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.1Just a little summary of the above: \[\lim_{x \rightarrow \infty} \frac{4}{9x+3}\]Divide both numerator and denominator by x\[\lim_{x \rightarrow \infty} \frac{\frac{4}{x}}{\frac{9x+3}{x}}\]\[=\lim_{x \rightarrow \infty} \frac{\frac{4}{x}}{9+\frac{3}{x}}\]\[= \frac{\lim_{x \rightarrow \infty}(\frac{4}{x})}{\lim_{x \rightarrow \infty}(9)+\lim_{x \rightarrow \infty}(\frac{3}{x})}\]And then evaluate the limit by using \[\lim_{x \rightarrow \infty}\frac{1}{x} = 0\]

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0One question, how did you know to divide by x at the first?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.