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ConDawg
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Evaluate the following limit. If the answer is positive infinite, type "I"; if negative infinite, type "N"; and if it does not exist, type "D".
lim > 4/9x+3
x goes to infinity
 one year ago
 one year ago
ConDawg Group Title
Evaluate the following limit. If the answer is positive infinite, type "I"; if negative infinite, type "N"; and if it does not exist, type "D". lim > 4/9x+3 x goes to infinity
 one year ago
 one year ago

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Callisto Group TitleBest ResponseYou've already chosen the best response.1
Is it \[\lim_{x \rightarrow \infty} \frac{4}{9x+3}\] for your question?
 one year ago

ConDawg Group TitleBest ResponseYou've already chosen the best response.0
yes sorry!! I was busy doing other practice questions for my test tomorrow.
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Never mind :) 1. Divide both numerator and denominator by x, what do you get?
 one year ago

ConDawg Group TitleBest ResponseYou've already chosen the best response.0
dw:1350532389029:dw
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Yup! Now, you need to know that \[\lim_{x \rightarrow \infty}\frac{1}{x} = 0\]Now, can you evaluate the limit?
 one year ago

ConDawg Group TitleBest ResponseYou've already chosen the best response.0
what does the 1/x = 0 mean? does that also mean that 4/x  0?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
It's \[\lim_{x \rightarrow \infty \frac{1}{x}} = 0\] Imagine 1 is divided by a very large number, then you probably get 0.
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Aww.. Bad typing! It's \[\lim_{x \rightarrow \infty} \frac{1}{x}=0\]
 one year ago

ConDawg Group TitleBest ResponseYou've already chosen the best response.0
so 4 divide by a very large number is pretty much 0, so I think the answer should be 0/9.
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Yup! Which is...?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
You got it!
 one year ago

ConDawg Group TitleBest ResponseYou've already chosen the best response.0
:) Thank you! It's greatly appreciated!
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Just a little summary of the above: \[\lim_{x \rightarrow \infty} \frac{4}{9x+3}\]Divide both numerator and denominator by x\[\lim_{x \rightarrow \infty} \frac{\frac{4}{x}}{\frac{9x+3}{x}}\]\[=\lim_{x \rightarrow \infty} \frac{\frac{4}{x}}{9+\frac{3}{x}}\]\[= \frac{\lim_{x \rightarrow \infty}(\frac{4}{x})}{\lim_{x \rightarrow \infty}(9)+\lim_{x \rightarrow \infty}(\frac{3}{x})}\]And then evaluate the limit by using \[\lim_{x \rightarrow \infty}\frac{1}{x} = 0\]
 one year ago

ConDawg Group TitleBest ResponseYou've already chosen the best response.0
One question, how did you know to divide by x at the first?
 one year ago
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