anonymous
  • anonymous
what is the solution of the system equation? -2x+y=3 8x-4y=-12
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
First solve for y in the first equation
anonymous
  • anonymous
Can you do it?
anonymous
  • anonymous
yeah its y=-2x+3

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anonymous
  • anonymous
Watch your negative sign
anonymous
  • anonymous
Do you want to use elimination method or substitution method to solve this problem?
anonymous
  • anonymous
substitution
anonymous
  • anonymous
Okay, retry to solve the first equation for y.
anonymous
  • anonymous
idk cause thats how i thought u do it
anonymous
  • anonymous
-2x + y = 3 +2x -2x + y = 3 + 2x y = 3 + 2x
anonymous
  • anonymous
are u sure??
anonymous
  • anonymous
You have to reverse the sign
anonymous
  • anonymous
yes
anonymous
  • anonymous
okay nvm i see how u did it
anonymous
  • anonymous
now we will substitute this into the second equation
anonymous
  • anonymous
8x - 4(3 + 2x) = -12
anonymous
  • anonymous
ok
anonymous
  • anonymous
can you solve for x by yourself now?
anonymous
  • anonymous
i got 0
anonymous
  • anonymous
There is something wrong. Double check your problem and make sure you typed the original correctly 8x - 12 - 8x = -12 0=0 The x term drops out completely, this shouldn't happen
anonymous
  • anonymous
yeah i guess so thats why i ased cause i was getting confused
anonymous
  • anonymous
I want to go back to this equation 8x - 12 - 8x = -12 rewritten as 8x - 12 = 8x - 12 lets get rid of the -12 8x = 8x then the 8's x=x So we can see that x equals all real numbers
anonymous
  • anonymous
This question is written badly. You are positive this is the correct question?
anonymous
  • anonymous
yes
anonymous
  • anonymous
I'm going to admit that I am confused as to our answer as well. Because x can equal anything which gives us an infinite amount of solutions. x=y/2 - 3/2 8(y/2 - 3/2) - 4y = -12 4y -12 - 4y = -12 y can be anything as well I'd say there is any infinite amount of solutions
anonymous
  • anonymous
This is a weird problem. Sry that I couln't help get an exact answer. All of our steps our correct, we didn't make any mistakes

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