sonja_lee2
what is the solution of the system equation?
-2x+y=3
8x-4y=-12
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wio
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First solve for y in the first equation
wio
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Can you do it?
sonja_lee2
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yeah its y=-2x+3
ChmE
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Watch your negative sign
ChmE
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Do you want to use elimination method or substitution method to solve this problem?
sonja_lee2
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substitution
ChmE
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Okay, retry to solve the first equation for y.
sonja_lee2
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idk cause thats how i thought u do it
ChmE
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-2x + y = 3
+2x -2x + y = 3 + 2x
y = 3 + 2x
sonja_lee2
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are u sure??
ChmE
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You have to reverse the sign
ChmE
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yes
sonja_lee2
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okay nvm i see how u did it
ChmE
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now we will substitute this into the second equation
ChmE
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8x - 4(3 + 2x) = -12
sonja_lee2
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ok
ChmE
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can you solve for x by yourself now?
sonja_lee2
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i got 0
ChmE
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There is something wrong. Double check your problem and make sure you typed the original correctly
8x - 12 - 8x = -12
0=0
The x term drops out completely, this shouldn't happen
sonja_lee2
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yeah i guess so thats why i ased cause i was getting confused
ChmE
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I want to go back to this equation 8x - 12 - 8x = -12
rewritten as 8x - 12 = 8x - 12
lets get rid of the -12
8x = 8x then the 8's
x=x
So we can see that x equals all real numbers
ChmE
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This question is written badly. You are positive this is the correct question?
sonja_lee2
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yes
ChmE
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I'm going to admit that I am confused as to our answer as well. Because x can equal anything which gives us an infinite amount of solutions.
x=y/2 - 3/2
8(y/2 - 3/2) - 4y = -12
4y -12 - 4y = -12
y can be anything as well
I'd say there is any infinite amount of solutions
ChmE
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This is a weird problem. Sry that I couln't help get an exact answer. All of our steps our correct, we didn't make any mistakes