Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

H1P2: DECOMPOSITION OF AMMONIUM NITRATE

OCW Scholar - Introduction to Solid State Chemistry
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

Solid NH4NO3 (ammonium nitrate) decomposes on heating to 400°C, forming N2O gas and water vapor, H2O. (a)Write a balanced chemical equation. incorrect (b) Calculate the number of grams of H2O that will form on decomposition of 0.10 mole of ammonium nitrate.
so first write the balanced equation, ill write it you balance it: NH4NO3 -> N2O + H2O and then from the reaction ratio you calculate mass of H2O produced from 0,1 mole of NH4NO3 n(H2O)/n(NH4NO3) = ?/? where ?/? is ratio from balanced chemical reaction and then n(H2O) = ?/? * n(NH4NO3) and n=m/M so m(H2O)= ?/? * n(NH4NO3) * M(H2O) any questions?
i have balanced the equation but im still uncertain how we make work out how many grams of h20 we can produce from 0.10 moles of amonium nitrate

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

NH4NO3 -> N2O + 2H2O -------------------------- n(H2O)/n(NH4NO3) = 2/1 = 2 so n(H2O) = 2 * n(NH4NO3) n(H2O) = 2*0,1 mol n(H2O) = 0,2 mol n=m/M m(H2O) = n(H2O) * M(H2O) m(H2O) = 0,2 mol * 18 g mol-1 m(H2O) = 3,6 g

Not the answer you are looking for?

Search for more explanations.

Ask your own question