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lgbasalloteBest ResponseYou've already chosen the best response.1
all you have to do is find the domain restriction. To do that, just equate x^2  1 to 0 then solve for x. got it?
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
just look at the denominator and find any discontinuitites
 one year ago

ggabbyBest ResponseYou've already chosen the best response.0
yea and i gotta but it in connotation
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
so you will have after a little factorising \[\frac{2x^3 + 5x^2  7x}{(x  1)(x + 1)}\] basically the discontinuity occurs when \[x^2 1 = 0\] to find the values of x factorised and then solve...
 one year ago
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