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ggabby

  • 3 years ago

hi whats the domain of 2x^3+5x^2-7x all over x^2-1

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  1. lgbasallote
    • 3 years ago
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    all you have to do is find the domain restriction. To do that, just equate x^2 - 1 to 0 then solve for x. got it?

  2. campbell_st
    • 3 years ago
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    just look at the denominator and find any discontinuitites

  3. ggabby
    • 3 years ago
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    yea and i gotta but it in connotation

  4. ggabby
    • 3 years ago
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    put

  5. campbell_st
    • 3 years ago
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    so you will have after a little factorising \[\frac{2x^3 + 5x^2 - 7x}{(x - 1)(x + 1)}\] basically the discontinuity occurs when \[x^2 -1 = 0\] to find the values of x factorised and then solve...

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