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lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
all you have to do is find the domain restriction. To do that, just equate x^2  1 to 0 then solve for x. got it?
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.0
just look at the denominator and find any discontinuitites
 one year ago

ggabby Group TitleBest ResponseYou've already chosen the best response.0
yea and i gotta but it in connotation
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.0
so you will have after a little factorising \[\frac{2x^3 + 5x^2  7x}{(x  1)(x + 1)}\] basically the discontinuity occurs when \[x^2 1 = 0\] to find the values of x factorised and then solve...
 one year ago
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