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kphilxo

  • 3 years ago

Calculate the percent yield for the following reaction if 233 g of NO2 reacted and 175 g of HNO3 were produced. 3NO2 + H2O 2HNO3+ NO

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  1. aaronq
    • 3 years ago
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    find how many moles were produced with respect to their coefficients .. divide one by the other and multiply by 100%

  2. kphilxo
    • 3 years ago
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    still confused

  3. aaronq
    • 3 years ago
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    sorry i misread the problem.. find the number of moles of reactant (NO2) n=m/MW ..moles = mass/ molecular weight then multiply by the coefficient ratio .. multiply times the molecular weight of HNO3 divide actual/ initial x 100% = you should get around 80%

  4. aaronq
    • 3 years ago
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    coeffcient ratio is x mol/ 3 NO2 = y mol/ 2 HNO3 and you're finding y so the ratio is 2/3

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