Calculate the percent yield for the following reaction if 233 g of NO2 reacted and 175 g of HNO3 were produced. 3NO2 + H2O 2HNO3+ NO

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Calculate the percent yield for the following reaction if 233 g of NO2 reacted and 175 g of HNO3 were produced. 3NO2 + H2O 2HNO3+ NO

Chemistry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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find how many moles were produced with respect to their coefficients .. divide one by the other and multiply by 100%
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sorry i misread the problem.. find the number of moles of reactant (NO2) n=m/MW ..moles = mass/ molecular weight then multiply by the coefficient ratio .. multiply times the molecular weight of HNO3 divide actual/ initial x 100% = you should get around 80%

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Other answers:

coeffcient ratio is x mol/ 3 NO2 = y mol/ 2 HNO3 and you're finding y so the ratio is 2/3

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