## YesterdayiSaidTomorow 3 years ago Use the properties of logarithms to expand the expression ln z(z-1)^2, z>1?

1. .UserNotFound.

Check it on yahoo . It says " = Ln (z) + Ln (z-1)^2 = Ln (z) + 2 Ln (z-1) "

2. YesterdayiSaidTomorow

that's the question I posted

3. YesterdayiSaidTomorow

and no one would explain

4. .UserNotFound.

amofide xD

5. amorfide

you have rules for logs if you have lnx² that is the same as saying 2lnx you can bring the power to the front of the log

6. YesterdayiSaidTomorow

but how do you separate it? Like Ln (z) + Ln (z-1)^2

7. YesterdayiSaidTomorow

i mean Ln (z) + 2 Ln (z-1)

8. amorfide

also you started with ln z(z-1)^2 there is another rule for logs if you have lna + ln b this is equal to lnab so you have ln z(z-1)^2 this is being multiplied, so we know we have two logs added together lnz + ln (z-1)²

9. YesterdayiSaidTomorow

Ooooooooooooooh

10. YesterdayiSaidTomorow

Thanks!

11. amorfide

anytime :D so lna+lnb=lnab lna-lnb=lna/b lna^b=blna i think there is another one i forget...