anonymous
  • anonymous
Use the properties of logarithms to expand the expression ln z(z-1)^2, z>1?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Check it on yahoo . It says " = Ln (z) + Ln (z-1)^2 = Ln (z) + 2 Ln (z-1) "
anonymous
  • anonymous
that's the question I posted
anonymous
  • anonymous
and no one would explain

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anonymous
  • anonymous
amofide xD
amorfide
  • amorfide
you have rules for logs if you have lnx² that is the same as saying 2lnx you can bring the power to the front of the log
anonymous
  • anonymous
but how do you separate it? Like Ln (z) + Ln (z-1)^2
anonymous
  • anonymous
i mean Ln (z) + 2 Ln (z-1)
amorfide
  • amorfide
also you started with ln z(z-1)^2 there is another rule for logs if you have lna + ln b this is equal to lnab so you have ln z(z-1)^2 this is being multiplied, so we know we have two logs added together lnz + ln (z-1)²
anonymous
  • anonymous
Ooooooooooooooh
anonymous
  • anonymous
Thanks!
amorfide
  • amorfide
anytime :D so lna+lnb=lnab lna-lnb=lna/b lna^b=blna i think there is another one i forget...

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