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Ruchi.

  • 3 years ago

please hlp me out

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  1. Ruchi.
    • 3 years ago
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    24. As the Aluminum rod and Copper rod joined are in parallel t Q = 1 Al t Cu Q t Q              l KA( 1 2 )    = l K A( ) l K1A( 1 2 ) 2 1 2         K = K1 + K2 = (390 + 200) = 590 t Q = l KA( 1 2 )    = 1 590 1104  (60  20) = 590 × 10–4 × 40 = 2.36 Watt

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