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anonymous
 4 years ago
How do you find the upper and lower bounds of a polynomial?
anonymous
 4 years ago
How do you find the upper and lower bounds of a polynomial?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For example, f(x) = 3x3 – 10x2 + 22x – 4.

hba
 4 years ago
Best ResponseYou've already chosen the best response.2Least Upper Bound and Greatest Lower Bound ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0as much as that's true, the question says to : determine between which consecutive integers the real zeros of each function are located.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0using the upper bound theorem, and f(x)/(xc), but i don't know what c is.

hba
 4 years ago
Best ResponseYou've already chosen the best response.2Are You Allowed To Use A Calculator ?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0You should have just mentioned what the original question was to begin with

hba
 4 years ago
Best ResponseYou've already chosen the best response.2. Plug in consecutive integers for x. The answer will be the two integers in which one gives you a positive value and one gives you a negative value. Start by trying the integers 3,2,1,0,1,2,3 for x.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0I can't understand why people think it is a good idea to ask half of the question rather then simply post the entire question. That's like giving partial info.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry @hero. I found the terminology confusing and thought people would understand upper bound meant the theorem.

hba
 4 years ago
Best ResponseYou've already chosen the best response.2If You Have A Calculator You Can Find The Zero :)

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0You mean you assumed that everyone else besides you were aware that such a theorem exists?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yep. oops. but thanks @hba. i think i got it.
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