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mathslover
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find the general solution for : \(\sin^2 \theta 2 \cos \theta + \frac{1}{4} = 0 \)
 one year ago
 one year ago
mathslover Group Title
find the general solution for : \(\sin^2 \theta 2 \cos \theta + \frac{1}{4} = 0 \)
 one year ago
 one year ago

This Question is Closed

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
\[Sin^2\theta = 1\cos^2 \theta\]
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
Nw Form a Quadratic Equation...
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
I got \(\theta = \cos^{1} \frac{1}{2}\)
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
theta = 60 degrees.
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
but general solution???
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
Just add 2k(360 degrees) where k is any integer, and there's your general solution :D
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
\[\cos \theta =\frac{ 1 }{ 2 }\] \[Cosx=Cosy\] then \[x=(2n \Pi)\pm y\]
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
wait, no, k(360 degrees) not 2k sorry
 one year ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
May I explain?
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
Yea @calculusfunctions sir, please!
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
\[x= (2n \Pi) \pm \frac{ \Pi }{ 3 }\]
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
I had got this : cos theta = 1/2 , please explain after this.
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
There Will be Two value For Cos x @mathslover
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
Yes but the negative one will NOT BE ACCEPTED..
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
as cos x can NOT BE NEGATIVE @Yahoo!
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
Why min value of cos x = 1 ....
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
Must x be in degrees?
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
theta rather
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
\[\cos 180 = 1\]
 one year ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
\[\sin ^{2}\theta 2\cos \theta +\frac{ 1 }{ 4 }=0\]First multiply the equation by the least common denominator.
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
Wait, there will be two values for cos theta , the other one is 5/2 but 5/2 , but since the minimum value of cos theta is 1 and hence it can not be 5/2 is this what we must think abt @Yahoo! ? (sorry for my above explanation as : cos theta can never be negative as I thought that we are talking about cos(theta) = cos theta)
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
cos(theta) \(\ne\) 5/2
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
Yup.....nw u r Correct
 one year ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
@mathslover Let me know when you're interested in learning a more efficient method.
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
@calculusfunctions sir, thanks a lot , I think I got it now.
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
Sorry but do you have any easier or another way?
 one year ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
Yes if you're interested.
 one year ago
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