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mathslover
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find the general solution for : \(\sin^2 \theta 2 \cos \theta + \frac{1}{4} = 0 \)
 2 years ago
 2 years ago
mathslover Group Title
find the general solution for : \(\sin^2 \theta 2 \cos \theta + \frac{1}{4} = 0 \)
 2 years ago
 2 years ago

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Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
\[Sin^2\theta = 1\cos^2 \theta\]
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
Nw Form a Quadratic Equation...
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
I got \(\theta = \cos^{1} \frac{1}{2}\)
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
theta = 60 degrees.
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
but general solution???
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
Just add 2k(360 degrees) where k is any integer, and there's your general solution :D
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
\[\cos \theta =\frac{ 1 }{ 2 }\] \[Cosx=Cosy\] then \[x=(2n \Pi)\pm y\]
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
wait, no, k(360 degrees) not 2k sorry
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
May I explain?
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
Yea @calculusfunctions sir, please!
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
\[x= (2n \Pi) \pm \frac{ \Pi }{ 3 }\]
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
I had got this : cos theta = 1/2 , please explain after this.
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
There Will be Two value For Cos x @mathslover
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
Yes but the negative one will NOT BE ACCEPTED..
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
as cos x can NOT BE NEGATIVE @Yahoo!
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
Why min value of cos x = 1 ....
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
Must x be in degrees?
 2 years ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
theta rather
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
\[\cos 180 = 1\]
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
\[\sin ^{2}\theta 2\cos \theta +\frac{ 1 }{ 4 }=0\]First multiply the equation by the least common denominator.
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
Wait, there will be two values for cos theta , the other one is 5/2 but 5/2 , but since the minimum value of cos theta is 1 and hence it can not be 5/2 is this what we must think abt @Yahoo! ? (sorry for my above explanation as : cos theta can never be negative as I thought that we are talking about cos(theta) = cos theta)
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
cos(theta) \(\ne\) 5/2
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
Yup.....nw u r Correct
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
@mathslover Let me know when you're interested in learning a more efficient method.
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
@calculusfunctions sir, thanks a lot , I think I got it now.
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
Sorry but do you have any easier or another way?
 2 years ago

calculusfunctions Group TitleBest ResponseYou've already chosen the best response.0
Yes if you're interested.
 2 years ago
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