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harrisc1221 Group Title

How would you simplify the square root of 45x^9

  • 2 years ago
  • 2 years ago

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  1. mayankdevnani Group Title
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    first, 45=9*5 square root of 9=3

    • 2 years ago
  2. mayankdevnani Group Title
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    ok

    • 2 years ago
  3. harrisc1221 Group Title
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    Ok, I've got that but the exponents are driving me crazy!!

    • 2 years ago
  4. calculusfunctions Group Title
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    Please teach. Do not give out solutions and hints @TheViper

    • 2 years ago
  5. TheViper Group Title
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    ok @calculusfunctions thanx:)

    • 2 years ago
  6. TheViper Group Title
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    @harrisc1221 first find the factors of 45

    • 2 years ago
  7. harrisc1221 Group Title
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    I've got that but I am so confused on how to factor the variables and exponents.

    • 2 years ago
  8. mayankdevnani Group Title
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    |dw:1350552721744:dw|

    • 2 years ago
  9. mayankdevnani Group Title
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    am i right @calculusfunctions

    • 2 years ago
  10. calculusfunctions Group Title
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    @harrisc1221 square root and square are inverse operations. In other words, the square root and the square undo each other. For example, if the square of 9 is 81, then the square root of 81 is 9. Understand so far before I continue.

    • 2 years ago
  11. harrisc1221 Group Title
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    Ok

    • 2 years ago
  12. TheViper Group Title
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    \[\large{\sqrt{45x^9}=\sqrt{5\times5\times3\times x\times x \times x\times x\times x\times x\times x\times x\times x}}\] \[\Large{=5\times x\times x\times x\times x\sqrt{3\times x}=5x^4\sqrt{3x}}\]

    • 2 years ago
  13. calculusfunctions Group Title
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    @mayankdevnani yes but you have to ask yourself if the student who is learning understands what you did and more importantly why you did what you did. This is why it's important to allow the student to arrive at the solutions themselves by guiding them, rather than simply saying here, this is how you answer this question. The student may understand this particular problem then but that doesn't help them solve future problems. A teachers job is to teach, not say, oh here let me solve it for you.

    • 2 years ago
  14. mayankdevnani Group Title
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    ok but my answer is right

    • 2 years ago
  15. harrisc1221 Group Title
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    Ok, so can you teach it to me calculusfunctions??

    • 2 years ago
  16. calculusfunctions Group Title
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    @TheViper yet you did it again.

    • 2 years ago
  17. calculusfunctions Group Title
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    Yes @harrisc1221

    • 2 years ago
  18. harrisc1221 Group Title
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    Ugh!!! I just need help figuring out how to simplify this problem!!!!

    • 2 years ago
  19. calculusfunctions Group Title
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    @harrisc1221 I was typing up a lesson for you and my comp lost the connection so allow me a few minutes to type it up again. Thanks.

    • 2 years ago
  20. harrisc1221 Group Title
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    Thank You @calculusfunctions

    • 2 years ago
  21. harrisc1221 Group Title
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    The actual assignment is multiplying radicals, but I can multiply them I just can't simplify them if they have variables and exponents.

    • 2 years ago
  22. calculusfunctions Group Title
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    \[\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}\] Example:\[\sqrt{54x ^{5}}=\sqrt{54}\sqrt{x ^{5}}\]Simplify each square root factor. First\[\sqrt{54}\]The greatest perfect square 54 is divisible by is 9. Thus\[\sqrt{54}=\sqrt{9}\sqrt{6}=3\sqrt{6}\]Next simplify\[\sqrt{x ^{5}}\]To find the square root of a variable, we divide the exponent by 2. Thus find the closest exponent that is divisible by 2. In our example the closest even number to 5 is 4. Thus\[\sqrt{x ^{5}}=\sqrt{x ^{4}}\sqrt{x}=x ^{2}\sqrt{x}\]Now\[\sqrt{54x ^{5}}=(3\sqrt{6})(x ^{2}\sqrt{x})=3x ^{2}\sqrt{6x}\]Understand @harrisc1221 ?

    • 2 years ago
  23. calculusfunctions Group Title
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    @harrisc1221 sorry it took longer because I lost the connection again.

    • 2 years ago
  24. calculusfunctions Group Title
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    Now @harrisc1221 could you please show me your solution if you understood so that I may see that you have the correct answer.

    • 2 years ago
  25. harrisc1221 Group Title
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    i've got 3*3*5*x^3*x^3

    • 2 years ago
  26. calculusfunctions Group Title
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    @Mpost1994 That is what I meant by teaching. As for your comment above, you're clearly not a psychic because FYI I am a teacher who loves teaching so much that I devote almost all my free time to help as many people as I can on this site and others. I would appreciate it if you did not waste anymore of mine and others valuable time.

    • 2 years ago
  27. calculusfunctions Group Title
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    @harrisc1221 is this your final answer?

    • 2 years ago
  28. harrisc1221 Group Title
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    No, it's what I have so far. I don't know how to write it out in the correct format @calculusfunctions

    • 2 years ago
  29. calculusfunctions Group Title
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    @harrisc1221 did you understand the lesson along with the example I gave?

    • 2 years ago
  30. harrisc1221 Group Title
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    Some of it said there was a path processing error

    • 2 years ago
  31. calculusfunctions Group Title
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    Obviously @Mpost1994 you have no respect for teachers.

    • 2 years ago
  32. harrisc1221 Group Title
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    math*

    • 2 years ago
  33. harrisc1221 Group Title
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    Can you all battle it out somewhere else, I came here because I am having trouble with this and the bickering back and forth is not making it any better!!!

    • 2 years ago
  34. calculusfunctions Group Title
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    I'm sorry @harrisc1221 I can't teach wile @Mpost1994 continues to be disruptive and obnoxious. @harrisc1221 let me know when he's gone.

    • 2 years ago
  35. Mpost1994 Group Title
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    I am leaving now. Sorry for saying something on your question post list. Bye now.

    • 2 years ago
  36. harrisc1221 Group Title
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    The least you could do is have respect for someone else!!!! I am the one that is having trouble with math and if you have a problem with what someone is saying then send them a message, but DON'T litter my message board with this crap!!

    • 2 years ago
  37. Mpost1994 Group Title
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    Your welcome.

    • 2 years ago
  38. Mpost1994 Group Title
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    I could always postpone bed and keep going.

    • 2 years ago
  39. harrisc1221 Group Title
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    If you're not willing to help I suggest you get off my question post!!! Gah, there is something called respect and you need to know what it is!! I came here as a last resort but unfortunately I can't even get any help here. So thank you for being a douchebag!!! I hope you're happy, because I am pissed!!!!!!

    • 2 years ago
  40. terenzreignz Group Title
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    hey, if I might interrupt? I'm sorry if I disrupt @calculusfunctions line of thought, but perhaps it might be easier to see things in terms of exponents?

    • 2 years ago
  41. harrisc1221 Group Title
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    Ok, what do you mean by that @terenzreignz

    • 2 years ago
  42. terenzreignz Group Title
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    Well, use laws of exponents to your advantage... Such as... \[(mn)^{p}=m^{p}n^{p}\]\[(m^{p})^{q}=m^{pq}\]\[\sqrt{m}=m^{\frac{1}{2}}\]

    • 2 years ago
  43. calculusfunctions Group Title
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    @terenzreignz go ahead because of @Mpost1994 I can't think anyway but as to your comment I did explain in terms of exponents.

    • 2 years ago
  44. calculusfunctions Group Title
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    *using exponents. Did you not read the lesson I posted above?

    • 2 years ago
  45. harrisc1221 Group Title
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    Am i the only one that keeps having the [math processing error] on their screen?

    • 2 years ago
  46. mathslover Group Title
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    @harrisc1221 try to press ctrl+F5

    • 2 years ago
  47. calculusfunctions Group Title
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    I've never ever been so disrespected by any student as I have today by @Mpost1994

    • 2 years ago
  48. harrisc1221 Group Title
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    It's still not showing up @mathslover

    • 2 years ago
  49. mathslover Group Title
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    @Mpost1994 , : as per openstudy code-of-conduct ( http://openstudy.com/code-of -conduct ) : Don't just provide the answer to a problem when someone else is in the middle of helping! But if you want to help, by all means, join in! So, I request you to NOT interrupt between the answer process of a user to the asker , I hope you will value the above point and will not devalue the question/answer process from now. Thanks! Oh btw , @harris1994 and @calculusfunctions I am impressed with both of your's discussion and interaction, this is the perfect use of OpenStudy .

    • 2 years ago
  50. calculusfunctions Group Title
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    @harrisc1221 \[\sqrt{45x ^{9}}=\sqrt{45}\sqrt{x ^{9}}\]Correct?

    • 2 years ago
  51. calculusfunctions Group Title
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    I'm not going to let the low lives like @Mpost 1994 detract me from teaching. He thinks he got to me but then that would like letting a terrorist win. Therefore I'm going to continue and not let scum bother me.

    • 2 years ago
  52. calculusfunctions Group Title
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    So @harrisc1221 let's continue shall we?

    • 2 years ago
  53. harrisc1221 Group Title
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    YES! @calculusfunctions

    • 2 years ago
  54. calculusfunctions Group Title
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    So first let's simplify\[\sqrt{45}\]first. Based on the example I gave, what do you think we should do first? Did you even read my example carefully?

    • 2 years ago
  55. harrisc1221 Group Title
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    we should simplify the square root of 54 first @calculusfunctions

    • 2 years ago
  56. calculusfunctions Group Title
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    Yes so then read the steps I explained to do that and simplify \[\sqrt{45}\]

    • 2 years ago
  57. harrisc1221 Group Title
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    which would be 3*3*5 @calculusfunctions

    • 2 years ago
  58. calculusfunctions Group Title
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    Yes the greatest perfect square that 54 is divisible by is 9. Thus??

    • 2 years ago
  59. harrisc1221 Group Title
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    I'm still having a hard time reading your input because of the math processing error, sorry.

    • 2 years ago
  60. calculusfunctions Group Title
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    \[\sqrt{45}=\sqrt{9}\sqrt{5}=?\]

    • 2 years ago
  61. calculusfunctions Group Title
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    I'm not sure why you're seeing error. I'm not experiencing the same issue.

    • 2 years ago
  62. harrisc1221 Group Title
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    \[\sqrt[3]{5}\]

    • 2 years ago
  63. harrisc1221 Group Title
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    I don't know either I have pushed ctrl and F5

    • 2 years ago
  64. calculusfunctions Group Title
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    LOL I think you mean\[3\sqrt{5}\]

    • 2 years ago
  65. harrisc1221 Group Title
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    I can only see you're reply if you tag me in the post for some reason @calculusfunctions

    • 2 years ago
  66. calculusfunctions Group Title
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    @harrisc1221 you mean\[3\sqrt{5}\]Do you see it now?

    • 2 years ago
  67. harrisc1221 Group Title
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    lol yes

    • 2 years ago
  68. calculusfunctions Group Title
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    Sorry @harrisc1221 but this @Mpost piece of disrespectful trash still keeps bothering me. The problem is that the moderators aren't around at the moment so he seem to taking advantage. But like I said we don't let terrorists win so let's continue.

    • 2 years ago
  69. calculusfunctions Group Title
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    @harrisc1221 next we have\[\sqrt{x ^{9}}\]The square root of a variable is found by dividing the the exponent of the variable by 2. This implies that the exponent must be even Thus what is the closest even number to 9?

    • 2 years ago
  70. harrisc1221 Group Title
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    8

    • 2 years ago
  71. calculusfunctions Group Title
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    @harrisc1221 correct so then\[\sqrt{x ^{9}}=?\]

    • 2 years ago
  72. mikala1 Group Title
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    wow alot has gone on here lol @calculusfunctions u r a great math teacher dont let any one tell you diffrent

    • 2 years ago
  73. harrisc1221 Group Title
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    x^8*x

    • 2 years ago
  74. lgbasallote Group Title
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    nice work here @calculusfunctions just the way it should be

    • 2 years ago
  75. calculusfunctions Group Title
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    Thank you @mikala1 It's because of decent, respectful, hardworking, motivated students like yourself, @harrisc1221, @mathslover, and many others that I will never stop and I refuse to allow a few individuals such as @Mpost 1994 to be problematic.

    • 2 years ago
  76. lgbasallote Group Title
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    this is actually an excellent example that solving by examples is a very efficient way of teaching

    • 2 years ago
  77. calculusfunctions Group Title
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    @lgbasallote thank you for your kind words. I appreciate the respect and the support from students like you, as I mentioned in the above comment. Thank you!!!!

    • 2 years ago
  78. lgbasallote Group Title
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    even more efficient than actually telling the first few steps of the solution P.S. <----not a student

    • 2 years ago
  79. calculusfunctions Group Title
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    @harrisc1221 yes\[\sqrt{x ^{9}}=\sqrt{x ^{8}}\sqrt{x}=?\]

    • 2 years ago
  80. calculusfunctions Group Title
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    LOL @lgbasallote I apologize. I didn't know you were not a student. Are you also a teacher?

    • 2 years ago
  81. harrisc1221 Group Title
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    Ok, so now I am lost after that last step

    • 2 years ago
  82. lgbasallote Group Title
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    i would assume "also" means you're a teacher? and yes, i am a liberal arts professor

    • 2 years ago
  83. calculusfunctions Group Title
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    @harrisc1221 What is \[\sqrt{x ^{8}}=?\]What did I say earlier about taking the square root of a variable?

    • 2 years ago
  84. harrisc1221 Group Title
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    It is divided by 2

    • 2 years ago
  85. calculusfunctions Group Title
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    @harrisc1221 what is divided by 2?

    • 2 years ago
  86. harrisc1221 Group Title
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    the exponent

    • 2 years ago
  87. calculusfunctions Group Title
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    @lgbasallote you assume correctly sir! I math and physics.

    • 2 years ago
  88. harrisc1221 Group Title
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    You would dived 8 by 2 and get 4

    • 2 years ago
  89. calculusfunctions Group Title
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    @harrisc1221 \[\sqrt{x ^{8}}=?\]

    • 2 years ago
  90. harrisc1221 Group Title
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    That is what I meant, I can't get the equation function to work right

    • 2 years ago
  91. harrisc1221 Group Title
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    then x = x

    • 2 years ago
  92. calculusfunctions Group Title
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    @harrisc1221 then\[\sqrt{x ^{9}}=\sqrt{x ^{8}}\sqrt{x}=?\]

    • 2 years ago
  93. calculusfunctions Group Title
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    @mikala1 I guess he's gone for now. He did message saying that he would have to go soon. I have to go in a bit as well but is there anything I can help you with before I do?

    • 2 years ago
  94. mikala1 Group Title
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    no i was just watching u do ur leaason so i could learn

    • 2 years ago
  95. calculusfunctions Group Title
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    @mikala1 that's great. Did you learn anything and are you good with those linear equations now?

    • 2 years ago
  96. mikala1 Group Title
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    just a little im not that far yet lol im only in 9 th grade

    • 2 years ago
  97. terenzreignz Group Title
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    @calculusfunctions Your patience is inspiring... It comes as no surprise that you're into teaching :D

    • 2 years ago
  98. calculusfunctions Group Title
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    @mikala1 yes i already knew you were in Grade 9 because you were studying linear equations.

    • 2 years ago
  99. calculusfunctions Group Title
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    @terenzreignz Thank you. I appreciate the encouragement.

    • 2 years ago
  100. mikala1 Group Title
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    lol just a little but i shall have more question next week for u

    • 2 years ago
  101. calculusfunctions Group Title
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    @mikala1 of course! Whenever you need me, simply let me know.

    • 2 years ago
  102. mikala1 Group Title
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    ok sheldon

    • 2 years ago
  103. mikala1 Group Title
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    loll

    • 2 years ago
  104. calculusfunctions Group Title
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    Haha! I see that I remain a mystery to you. LOL. But seriously I appreciate the compliment, although I don't see myself as being as intelligent as Sheldon.

    • 2 years ago
  105. mikala1 Group Title
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    u r for real lol and hes real not that smart in dating world lol

    • 2 years ago
  106. calculusfunctions Group Title
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    LOL. I love that show!! My ringtone is the theme song.

    • 2 years ago
  107. calculusfunctions Group Title
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    Anyway I have to go now but you like I said, you let me know if you want my help. Alright?

    • 2 years ago
  108. mikala1 Group Title
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    lol u rwaly do sound like him thogh n ok

    • 2 years ago
  109. mikala1 Group Title
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    have a great day

    • 2 years ago
  110. calculusfunctions Group Title
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    You too! Bye!

    • 2 years ago
  111. harrisc1221 Group Title
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    Yeah still needing help with help with this

    • 2 years ago
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is replying to Can someone tell me what button the professor is hitting...

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