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harrisc1221

How would you simplify the square root of 45x^9

  • one year ago
  • one year ago

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  1. mayankdevnani
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    first, 45=9*5 square root of 9=3

    • one year ago
  2. mayankdevnani
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    ok

    • one year ago
  3. harrisc1221
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    Ok, I've got that but the exponents are driving me crazy!!

    • one year ago
  4. calculusfunctions
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    Please teach. Do not give out solutions and hints @TheViper

    • one year ago
  5. TheViper
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    ok @calculusfunctions thanx:)

    • one year ago
  6. TheViper
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    @harrisc1221 first find the factors of 45

    • one year ago
  7. harrisc1221
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    I've got that but I am so confused on how to factor the variables and exponents.

    • one year ago
  8. mayankdevnani
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    |dw:1350552721744:dw|

    • one year ago
  9. mayankdevnani
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    am i right @calculusfunctions

    • one year ago
  10. calculusfunctions
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    @harrisc1221 square root and square are inverse operations. In other words, the square root and the square undo each other. For example, if the square of 9 is 81, then the square root of 81 is 9. Understand so far before I continue.

    • one year ago
  11. harrisc1221
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    Ok

    • one year ago
  12. TheViper
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    \[\large{\sqrt{45x^9}=\sqrt{5\times5\times3\times x\times x \times x\times x\times x\times x\times x\times x\times x}}\] \[\Large{=5\times x\times x\times x\times x\sqrt{3\times x}=5x^4\sqrt{3x}}\]

    • one year ago
  13. calculusfunctions
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    @mayankdevnani yes but you have to ask yourself if the student who is learning understands what you did and more importantly why you did what you did. This is why it's important to allow the student to arrive at the solutions themselves by guiding them, rather than simply saying here, this is how you answer this question. The student may understand this particular problem then but that doesn't help them solve future problems. A teachers job is to teach, not say, oh here let me solve it for you.

    • one year ago
  14. mayankdevnani
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    ok but my answer is right

    • one year ago
  15. harrisc1221
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    Ok, so can you teach it to me calculusfunctions??

    • one year ago
  16. calculusfunctions
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    @TheViper yet you did it again.

    • one year ago
  17. calculusfunctions
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    Yes @harrisc1221

    • one year ago
  18. harrisc1221
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    Ugh!!! I just need help figuring out how to simplify this problem!!!!

    • one year ago
  19. calculusfunctions
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    @harrisc1221 I was typing up a lesson for you and my comp lost the connection so allow me a few minutes to type it up again. Thanks.

    • one year ago
  20. harrisc1221
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    Thank You @calculusfunctions

    • one year ago
  21. harrisc1221
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    The actual assignment is multiplying radicals, but I can multiply them I just can't simplify them if they have variables and exponents.

    • one year ago
  22. calculusfunctions
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    \[\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}\] Example:\[\sqrt{54x ^{5}}=\sqrt{54}\sqrt{x ^{5}}\]Simplify each square root factor. First\[\sqrt{54}\]The greatest perfect square 54 is divisible by is 9. Thus\[\sqrt{54}=\sqrt{9}\sqrt{6}=3\sqrt{6}\]Next simplify\[\sqrt{x ^{5}}\]To find the square root of a variable, we divide the exponent by 2. Thus find the closest exponent that is divisible by 2. In our example the closest even number to 5 is 4. Thus\[\sqrt{x ^{5}}=\sqrt{x ^{4}}\sqrt{x}=x ^{2}\sqrt{x}\]Now\[\sqrt{54x ^{5}}=(3\sqrt{6})(x ^{2}\sqrt{x})=3x ^{2}\sqrt{6x}\]Understand @harrisc1221 ?

    • one year ago
  23. calculusfunctions
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    @harrisc1221 sorry it took longer because I lost the connection again.

    • one year ago
  24. calculusfunctions
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    Now @harrisc1221 could you please show me your solution if you understood so that I may see that you have the correct answer.

    • one year ago
  25. harrisc1221
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    i've got 3*3*5*x^3*x^3

    • one year ago
  26. calculusfunctions
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    @Mpost1994 That is what I meant by teaching. As for your comment above, you're clearly not a psychic because FYI I am a teacher who loves teaching so much that I devote almost all my free time to help as many people as I can on this site and others. I would appreciate it if you did not waste anymore of mine and others valuable time.

    • one year ago
  27. calculusfunctions
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    @harrisc1221 is this your final answer?

    • one year ago
  28. harrisc1221
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    No, it's what I have so far. I don't know how to write it out in the correct format @calculusfunctions

    • one year ago
  29. calculusfunctions
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    @harrisc1221 did you understand the lesson along with the example I gave?

    • one year ago
  30. harrisc1221
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    Some of it said there was a path processing error

    • one year ago
  31. calculusfunctions
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    Obviously @Mpost1994 you have no respect for teachers.

    • one year ago
  32. harrisc1221
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    math*

    • one year ago
  33. harrisc1221
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    Can you all battle it out somewhere else, I came here because I am having trouble with this and the bickering back and forth is not making it any better!!!

    • one year ago
  34. calculusfunctions
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    I'm sorry @harrisc1221 I can't teach wile @Mpost1994 continues to be disruptive and obnoxious. @harrisc1221 let me know when he's gone.

    • one year ago
  35. Mpost1994
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    I am leaving now. Sorry for saying something on your question post list. Bye now.

    • one year ago
  36. harrisc1221
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    The least you could do is have respect for someone else!!!! I am the one that is having trouble with math and if you have a problem with what someone is saying then send them a message, but DON'T litter my message board with this crap!!

    • one year ago
  37. Mpost1994
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    Your welcome.

    • one year ago
  38. Mpost1994
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    I could always postpone bed and keep going.

    • one year ago
  39. harrisc1221
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    If you're not willing to help I suggest you get off my question post!!! Gah, there is something called respect and you need to know what it is!! I came here as a last resort but unfortunately I can't even get any help here. So thank you for being a douchebag!!! I hope you're happy, because I am pissed!!!!!!

    • one year ago
  40. terenzreignz
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    hey, if I might interrupt? I'm sorry if I disrupt @calculusfunctions line of thought, but perhaps it might be easier to see things in terms of exponents?

    • one year ago
  41. harrisc1221
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    Ok, what do you mean by that @terenzreignz

    • one year ago
  42. terenzreignz
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    Well, use laws of exponents to your advantage... Such as... \[(mn)^{p}=m^{p}n^{p}\]\[(m^{p})^{q}=m^{pq}\]\[\sqrt{m}=m^{\frac{1}{2}}\]

    • one year ago
  43. calculusfunctions
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    @terenzreignz go ahead because of @Mpost1994 I can't think anyway but as to your comment I did explain in terms of exponents.

    • one year ago
  44. calculusfunctions
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    *using exponents. Did you not read the lesson I posted above?

    • one year ago
  45. harrisc1221
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    Am i the only one that keeps having the [math processing error] on their screen?

    • one year ago
  46. mathslover
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    @harrisc1221 try to press ctrl+F5

    • one year ago
  47. calculusfunctions
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    I've never ever been so disrespected by any student as I have today by @Mpost1994

    • one year ago
  48. harrisc1221
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    It's still not showing up @mathslover

    • one year ago
  49. mathslover
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    @Mpost1994 , : as per openstudy code-of-conduct ( http://openstudy.com/code-of -conduct ) : Don't just provide the answer to a problem when someone else is in the middle of helping! But if you want to help, by all means, join in! So, I request you to NOT interrupt between the answer process of a user to the asker , I hope you will value the above point and will not devalue the question/answer process from now. Thanks! Oh btw , @harris1994 and @calculusfunctions I am impressed with both of your's discussion and interaction, this is the perfect use of OpenStudy .

    • one year ago
  50. calculusfunctions
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    @harrisc1221 \[\sqrt{45x ^{9}}=\sqrt{45}\sqrt{x ^{9}}\]Correct?

    • one year ago
  51. calculusfunctions
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    I'm not going to let the low lives like @Mpost 1994 detract me from teaching. He thinks he got to me but then that would like letting a terrorist win. Therefore I'm going to continue and not let scum bother me.

    • one year ago
  52. calculusfunctions
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    So @harrisc1221 let's continue shall we?

    • one year ago
  53. harrisc1221
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    YES! @calculusfunctions

    • one year ago
  54. calculusfunctions
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    So first let's simplify\[\sqrt{45}\]first. Based on the example I gave, what do you think we should do first? Did you even read my example carefully?

    • one year ago
  55. harrisc1221
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    we should simplify the square root of 54 first @calculusfunctions

    • one year ago
  56. calculusfunctions
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    Yes so then read the steps I explained to do that and simplify \[\sqrt{45}\]

    • one year ago
  57. harrisc1221
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    which would be 3*3*5 @calculusfunctions

    • one year ago
  58. calculusfunctions
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    Yes the greatest perfect square that 54 is divisible by is 9. Thus??

    • one year ago
  59. harrisc1221
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    I'm still having a hard time reading your input because of the math processing error, sorry.

    • one year ago
  60. calculusfunctions
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    \[\sqrt{45}=\sqrt{9}\sqrt{5}=?\]

    • one year ago
  61. calculusfunctions
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    I'm not sure why you're seeing error. I'm not experiencing the same issue.

    • one year ago
  62. harrisc1221
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    \[\sqrt[3]{5}\]

    • one year ago
  63. harrisc1221
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    I don't know either I have pushed ctrl and F5

    • one year ago
  64. calculusfunctions
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    LOL I think you mean\[3\sqrt{5}\]

    • one year ago
  65. harrisc1221
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    I can only see you're reply if you tag me in the post for some reason @calculusfunctions

    • one year ago
  66. calculusfunctions
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    @harrisc1221 you mean\[3\sqrt{5}\]Do you see it now?

    • one year ago
  67. harrisc1221
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    lol yes

    • one year ago
  68. calculusfunctions
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    Sorry @harrisc1221 but this @Mpost piece of disrespectful trash still keeps bothering me. The problem is that the moderators aren't around at the moment so he seem to taking advantage. But like I said we don't let terrorists win so let's continue.

    • one year ago
  69. calculusfunctions
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    @harrisc1221 next we have\[\sqrt{x ^{9}}\]The square root of a variable is found by dividing the the exponent of the variable by 2. This implies that the exponent must be even Thus what is the closest even number to 9?

    • one year ago
  70. harrisc1221
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    8

    • one year ago
  71. calculusfunctions
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    @harrisc1221 correct so then\[\sqrt{x ^{9}}=?\]

    • one year ago
  72. mikala1
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    wow alot has gone on here lol @calculusfunctions u r a great math teacher dont let any one tell you diffrent

    • one year ago
  73. harrisc1221
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    x^8*x

    • one year ago
  74. lgbasallote
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    nice work here @calculusfunctions just the way it should be

    • one year ago
  75. calculusfunctions
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    Thank you @mikala1 It's because of decent, respectful, hardworking, motivated students like yourself, @harrisc1221, @mathslover, and many others that I will never stop and I refuse to allow a few individuals such as @Mpost 1994 to be problematic.

    • one year ago
  76. lgbasallote
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    this is actually an excellent example that solving by examples is a very efficient way of teaching

    • one year ago
  77. calculusfunctions
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    @lgbasallote thank you for your kind words. I appreciate the respect and the support from students like you, as I mentioned in the above comment. Thank you!!!!

    • one year ago
  78. lgbasallote
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    even more efficient than actually telling the first few steps of the solution P.S. <----not a student

    • one year ago
  79. calculusfunctions
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    @harrisc1221 yes\[\sqrt{x ^{9}}=\sqrt{x ^{8}}\sqrt{x}=?\]

    • one year ago
  80. calculusfunctions
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    LOL @lgbasallote I apologize. I didn't know you were not a student. Are you also a teacher?

    • one year ago
  81. harrisc1221
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    Ok, so now I am lost after that last step

    • one year ago
  82. lgbasallote
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    i would assume "also" means you're a teacher? and yes, i am a liberal arts professor

    • one year ago
  83. calculusfunctions
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    @harrisc1221 What is \[\sqrt{x ^{8}}=?\]What did I say earlier about taking the square root of a variable?

    • one year ago
  84. harrisc1221
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    It is divided by 2

    • one year ago
  85. calculusfunctions
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    @harrisc1221 what is divided by 2?

    • one year ago
  86. harrisc1221
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    the exponent

    • one year ago
  87. calculusfunctions
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    @lgbasallote you assume correctly sir! I math and physics.

    • one year ago
  88. harrisc1221
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    You would dived 8 by 2 and get 4

    • one year ago
  89. calculusfunctions
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    @harrisc1221 \[\sqrt{x ^{8}}=?\]

    • one year ago
  90. harrisc1221
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    That is what I meant, I can't get the equation function to work right

    • one year ago
  91. harrisc1221
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    then x = x

    • one year ago
  92. calculusfunctions
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    @harrisc1221 then\[\sqrt{x ^{9}}=\sqrt{x ^{8}}\sqrt{x}=?\]

    • one year ago
  93. calculusfunctions
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    @mikala1 I guess he's gone for now. He did message saying that he would have to go soon. I have to go in a bit as well but is there anything I can help you with before I do?

    • one year ago
  94. mikala1
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    no i was just watching u do ur leaason so i could learn

    • one year ago
  95. calculusfunctions
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    @mikala1 that's great. Did you learn anything and are you good with those linear equations now?

    • one year ago
  96. mikala1
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    just a little im not that far yet lol im only in 9 th grade

    • one year ago
  97. terenzreignz
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    @calculusfunctions Your patience is inspiring... It comes as no surprise that you're into teaching :D

    • one year ago
  98. calculusfunctions
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    @mikala1 yes i already knew you were in Grade 9 because you were studying linear equations.

    • one year ago
  99. calculusfunctions
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    @terenzreignz Thank you. I appreciate the encouragement.

    • one year ago
  100. mikala1
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    lol just a little but i shall have more question next week for u

    • one year ago
  101. calculusfunctions
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    @mikala1 of course! Whenever you need me, simply let me know.

    • one year ago
  102. mikala1
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    ok sheldon

    • one year ago
  103. mikala1
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    loll

    • one year ago
  104. calculusfunctions
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    Haha! I see that I remain a mystery to you. LOL. But seriously I appreciate the compliment, although I don't see myself as being as intelligent as Sheldon.

    • one year ago
  105. mikala1
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    u r for real lol and hes real not that smart in dating world lol

    • one year ago
  106. calculusfunctions
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    LOL. I love that show!! My ringtone is the theme song.

    • one year ago
  107. calculusfunctions
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    Anyway I have to go now but you like I said, you let me know if you want my help. Alright?

    • one year ago
  108. mikala1
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    lol u rwaly do sound like him thogh n ok

    • one year ago
  109. mikala1
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    have a great day

    • one year ago
  110. calculusfunctions
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    You too! Bye!

    • one year ago
  111. harrisc1221
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    Yeah still needing help with help with this

    • one year ago
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