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x^8=y^2+87 Find all the values of x and y for which x and y are prime numbers.

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hehehehe u thought u where gonna get the answer xD
Sorry, but I know the answer as this question is mine.

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Oh... What an easy question..! I don't want to solve it.. Ha ha ha ha...
Sorry the question is little changed.
is this allowed ? (x^4-y)(x^4+y) = 87 since it's either 87*1 or 29*3 we need x^4-y =1 and x^4+y=87 we wont get here prime number for x or x^4-y=3 x^4+y=29 2x^4 = 32 x^4 = 16 x = 2 y = 13 so only x = 2 and y = 13 ?
Ya...... that looks correct.

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