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mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0@calculusfunctions sir.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0I had come up with : tan (A+B) = 1

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3\[\tan(A+B) = \frac{\tan(A) + \tan(B)}{1  \tan(A) \cdot \tan(B)}\]

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.045 = pi/4 180 = pi so pi/4 + pi = 3pi/4 pi/4 + 2pi = 7pi/4 and so on..

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3If you calculated it right then: \[A+B= \tan^{1}(1)\]

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0so 7pi/4 is one possibility

03453660
 2 years ago
Best ResponseYou've already chosen the best response.1\[A+B = \tan^{1}\frac{ 1 }{ 2 }+\tan^{1} \frac{ 1 }{ 3 }\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0so it can be : 3 pi / 4, 7pi/4 , . ... It can not be 5 pi / 4 because it will be positive for tan.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0But the book says that the answer is : d) none Options were : i) pi/4 ii) 3 pi/4 iii) 5 pi/4 iv) none.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0So it will be 3 pi/4 ? or none?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2it will be 3pi/4 are any constraints given?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2like A+B should be between 0 to 90 or something like this ?

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.0ok thanks a lot @hartnn :)

sara12345
 2 years ago
Best ResponseYou've already chosen the best response.0wud tan(A+B) formula work for all angles

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3\[\pi  \frac{\pi}{4} = \frac{3 \pi}{4}\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.3There was some mistake in the formula that I had written above.. That day I was looking for the same and now I have found it : \[\tan^{1}(x) = \pi  \tan^{1}(x)\]
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