## charlotteakina Help!? PLEASE! Screenshot attached! 2 questions! 1 question answered! ONE TO GO! one year ago one year ago

1. Coolsector

5 people means 3.6 seconds so y people will be t seconds we can show it this way : |dw:1350566474324:dw|

2. Coolsector

now cross multiply and get the connection between y (number of people) and t (seconds)

3. Coolsector

and hey .. how are you ? :)

4. Decart

$t=.72p$

5. Coolsector

|dw:1350566721091:dw|

6. Coolsector

if you multiply one side by 100 you should multiply the other by 100 too

7. Coolsector

we need to isolate t from the equation that i gave you

8. Coolsector

no .. it's final answer is correct but i want you to be able to get it by yourself

9. Coolsector

there is no 75 in decart's answer :|

10. Coolsector

$\frac{ 5 }{ y } = \frac{ 3.6 }{ t }$ multiply both sides by $y \times t$ we get: $5t = 3.6y$ now divide both sides of the equation by 5 we get: $t = \frac{ 3.6 }{ 5 } \times y$ which is the same as $t=0.72y$

11. Coolsector

yes sorry i was washing dishes lol

12. Coolsector

division of two fractions is like multiplying the first by the reciprocal of the second

13. Coolsector

$\frac{ a }{ b } \div \frac{ c }{ d } = \frac{ a }{ b } \times \frac{ d }{ c }$

14. Coolsector

so you can rewrite the problem as .. ?

15. Coolsector

no i just gave an example

16. Coolsector

you have to multiply the first fraction by the reciprocal of the second..

17. Coolsector

|dw:1350568226013:dw|

18. Coolsector

yes .. and changed the division to multiplication this his how you divide two fractions..

19. Coolsector

$\frac{ (x^2-x-6)(x^2+5x+4) }{ (x^2-2x-3)(x^2+x-12) }$

20. Coolsector

this is now what you have to simplify "so, do I multiply x^2 + x - 12 by x^2 + 5x + 4 now? " no.. why you say that ?

21. Coolsector

$\frac{ a }{ b } \neq a * b$

22. Coolsector

we changed the division to multiplication because we divided FRACTION BY FRACTION

23. Coolsector

no it's not right

24. Coolsector

$\frac{ 5 }{ 3 } * \frac{ 4 }{ 2 } = ?$

25. Coolsector

26. Coolsector

right you just multiplied 5 with 4 and divided by the multiplication of 3 with 2

27. Coolsector

|dw:1350569102823:dw|

28. Coolsector

so same here .. after we changed the division into multiplication it's just multiplication of two fractions

29. Coolsector

you tell me .. how do we multiply those two fractions ?

30. Coolsector

i wont get mad why would i :| look : $\frac{ x^2-x-6 }{ x^2-2x-3 } \times \frac{ x^2+5x+4 }{ x^2+x-12 } = \frac{ (x^2-x-6)(x^2+5x+4) }{ (x^2-2x-3)(x^2+x-12) }$

31. Coolsector

i dont know why you multiply numerator by denominator

32. Coolsector

this is what you get after the multiplication of the two fractions now we better factor every term than open the brackes like x^2-x-6 = x^2-3x+2x-6 = x(x-3)+2(x-3) = (x+2)(x-3)

33. Coolsector

yes look : whenever there is multiplication of two fractions you multiply numerator by numerator and denom by denom.. whenever there is division of two fractions you keep the first fraction as it is you change the division into multiplication but then for the second fraction you flip numerator and denominator and then you have multiplication of two fractions..

34. Coolsector

yes as i wrote up there

35. LCK

I'll just to butt in for a bit, the general flow of fraction division goes like this: 1. Turn the division into a multiplication by inverting the second fraction 2. Factorise as much as possible and eliminate common terms. 3. Solve by multiplying the numerator by the numerator and denominator by denominator. Yes I wrote the same thing as cool sorry :/.

36. Coolsector

now it's better to factor every term than open the brackets .. so factoring x^2-x-6 gives = x^2-3x+2x-6 = x(x-3)+2(x-3) = (x+2)(x-3)

37. Coolsector

can you factor the rest of the terms ?

38. Coolsector

yes.. i just showed the way

39. Coolsector

you see my last expression is (x+2)(x-3)

40. Coolsector

now factor the rest of the terms .. what do you get ?

41. Coolsector

so are you factoring the rest ?

42. Coolsector

good so how the expression looks like ?

43. Coolsector

after you change every term by it's factored form

44. Coolsector

you have to replace every term by it's factored from like replaceing " x^2 - x- 6" by " (x+2)(x-3) " in the last expression

45. Coolsector

very good

46. Coolsector

now you can eliminate some of them..

47. Coolsector

if you have the same thing in the numerator and in the denominator you can eliminate it ..

48. Coolsector

and one more ..

49. Coolsector

|dw:1350571449666:dw|

50. Coolsector

so what is left .. $\frac{ x+2 }{ x-3 }$

51. Coolsector

yes

52. Coolsector

yw :)

53. Coolsector

i hope the next question of this kind will be easier for you now that you know the steps

54. Coolsector