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Given L_1=<-2,3,-1>+t<2,-3,-5> and 2x1-3x2-5x3=5 Find the intersection point between the line and the plane.

Mathematics
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x1 = -2+2t <-- put these values in the plane and find the value of t.
What should i do with x2 and x3?
x2=3-3t?

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Other answers:

and x3=-1-5t?
yeah!!
ok one second...
Okay, I got t=13/38. So plugging that back into my line equation, I get the point <-25/19,75/38,65/38>.
well ... put those point on the plane and check if it's correct or not.
Thanks!
@experimentX Could you do work out this problem and do a quick check of the values? I followed your instructions but when I plug them back in to the line equation and the plane equation, I don't get the same position vector....
sorry ... had connection problem.
that's okay, solve my problem, like just now lol
solved*
i made a sign error....darn. Took forever to find it lol
oh ... good for you!!

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