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derrick902

  • 3 years ago

Given L_1=<-2,3,-1>+t<2,-3,-5> and 2x1-3x2-5x3=5 Find the intersection point between the line and the plane.

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  1. experimentX
    • 3 years ago
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    x1 = -2+2t <-- put these values in the plane and find the value of t.

  2. derrick902
    • 3 years ago
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    What should i do with x2 and x3?

  3. derrick902
    • 3 years ago
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    x2=3-3t?

  4. derrick902
    • 3 years ago
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    and x3=-1-5t?

  5. experimentX
    • 3 years ago
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    yeah!!

  6. derrick902
    • 3 years ago
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    ok one second...

  7. derrick902
    • 3 years ago
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    Okay, I got t=13/38. So plugging that back into my line equation, I get the point <-25/19,75/38,65/38>.

  8. experimentX
    • 3 years ago
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    well ... put those point on the plane and check if it's correct or not.

  9. derrick902
    • 3 years ago
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    Thanks!

  10. derrick902
    • 3 years ago
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    @experimentX Could you do work out this problem and do a quick check of the values? I followed your instructions but when I plug them back in to the line equation and the plane equation, I don't get the same position vector....

  11. experimentX
    • 3 years ago
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    sorry ... had connection problem.

  12. derrick902
    • 3 years ago
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    that's okay, solve my problem, like just now lol

  13. derrick902
    • 3 years ago
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    solved*

  14. derrick902
    • 3 years ago
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    i made a sign error....darn. Took forever to find it lol

  15. experimentX
    • 3 years ago
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    oh ... good for you!!

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