At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

\[\lim_{x \rightarrow -\infty} \frac{ \sqrt{x ^2 + 8} -3 }{ 1- x }\]

Multiply top and bottom by \[1/\sqrt{x^2}\]

\[\lim_{x \rightarrow \infty}\frac{\sqrt{\frac{x^2+8}{x^2}}-\frac{3}{x}}{\frac{1}{x}-1}\]

the answer shouldn't be 1
...

You forgot something. The x before those expressions.

Now I am getting a -1, as you are implying. Thats weird. I need to recheck.

What do you mean the x before the expressions?

right -1 is what i got

So the question was suppose to be
\[\lim_{x \rightarrow - \infty}\frac{\sqrt{x^2+8}-3}{1-x}\]

Yes. I typed it right the first time.

\[|x|=-x \text{ if } x<0\]

But I still get a -1. I checked with Wolfram it gets +1.

Absolute value, Im following. Got the same.

Yep the limit is 1 if x->-inf

lol. Thanks.