Find the intersection point between two lines:
L1=<-3,5,7>k+<1,-2,-0>
L2=<3,-1,-4>t+<1,2,3>

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

- anonymous

Find the intersection point between two lines:
L1=<-3,5,7>k+<1,-2,-0>
L2=<3,-1,-4>t+<1,2,3>

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- experimentX

just equate the values of x, y, z from those two lines and find the valeus of k and t.
if you don't find singular values ... then they do not intersect.

- anonymous

Hey @experimentX . I tried solving this intersection using a similar method you showed me for the line and plane intersection, does it work here as well?

- anonymous

Yeah, I found the intersection using the x,y,z components from L1 and L2 and found the correct intersection. I was just wondering if we could solve it using the other way you showed me for the line and plane problem

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- experimentX

yeah it works .... just try to find the value of k and t ... from first two equation. put the value on the last equation. If it's invalid then the line does not intersect.

- anonymous

Okay, so far I have from L2:
1+3t -->k1
2-t ---->k2
3-4t--->k3
and L1:
-3k1+5k2+7k3=1
Filling those values from L2 into L1, I get:
1=-3(1+3t)+5(2-t)+7(3-4t)
1=-3-9t+10-5t+21-28t
t=27/42

- experimentX

lol ... what are you doing??
|dw:1350576239788:dw|

- anonymous

Was what I did not the way i'm suppose to do it? lol

- anonymous

I just tried to do it a similar way to the way we solved the line and plane intersection; breaking up the line equation into it's x,y,z components, then filling them into the plane equation, except here there's two lines, so I broke up one of the line equations into it's x,y,z, and filled it into the other line equation

- experimentX

you are making it complicated... we are trying to find the point common to both lines. so just equate
x, y and z of both lines.

- anonymous

Got it, thanks :D

- experimentX

well ... trying to find a plane that would contain both lines is not bad either. good pratice for other problems!

Looking for something else?

Not the answer you are looking for? Search for more explanations.