A community for students.
Here's the question you clicked on:
 0 viewing
JadeEyes
 2 years ago
As a seasonal amusement some programmers like to print out a picture of a Christmas Tree looking like this.
*
***
*
***
*****
*
***
*****
*******

+
The tree consists of a series of tiers (three in this case) of increasing size. Write a program to produce such a display having prompted the user for thw number of tiers. You could try a few baubles on the tree (using o or O).
JadeEyes
 2 years ago
As a seasonal amusement some programmers like to print out a picture of a Christmas Tree looking like this. * *** * *** ***** * *** ***** *******  + The tree consists of a series of tiers (three in this case) of increasing size. Write a program to produce such a display having prompted the user for thw number of tiers. You could try a few baubles on the tree (using o or O).

This Question is Closed

eSpeX
 2 years ago
Best ResponseYou've already chosen the best response.0What language are you writing in, what have you already tried, and what is giving you difficulties?

JadeEyes
 2 years ago
Best ResponseYou've already chosen the best response.0I'm using C language..!! I have no difficulties with the language itself..!! It's the logic that I lack..!! :P ..!! I just can't figue out how to use loops to achieve the wanted result..!! Can you help me with that..?? :)..!!

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0print characters 3 characters next time 5 characters .. 7 ... etc etc

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0i haven't programmed C for very long time. do something like this for(i=1;i<= 3, i++) { for(k=2i+1; k >= 1; k++) { for(j=1; j<= 2i+1) { print on center here } } }

JadeEyes
 2 years ago
Best ResponseYou've already chosen the best response.0@eSpeX That's how tried doing it the first time using while loop : n = number of tiers while(n!=0) { printf( * \n) printf(O***O\n) n while(n!=0) { printf( * \n) printf( *** \n) printf( ***** \n) n } while(n!=0)...and so on..!! } But then it's kind of an infinite thing..!! ..@experimentX Thank you..!! However I don't really understand how it works..!!

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0i don't seem to have c compiler in my computer .. mind if I send you python code?

JadeEyes
 2 years ago
Best ResponseYou've already chosen the best response.0I'll try to decode it back to C..!! :P ..!! So don't worry..!! :) ..!!

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0i ended up codig this in java public class Christmas{ public static void main(String args[]){ int i, j, k; for(i=1; i <= 3; i++){ for(j=i+1; j>=1; j){ for(k=1; k<=2*i+1; k++){ if(k >= j && k <= j + 2*(i+1)) System.out.print("*"); else System.out.print(" "); } System.out.println(""); } } } }

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.0this is the working code in Java public class Christmas{ public static void main(String args[]){ int i, j, k, l=3; for(i=1; i <= l; i++){ for(j=i+1; j>=1; j){ for(int x=1; x<=li; x++) System.out.print(" "); for(k=1; k<=2*l+1; k++){ if(k >= j && k <= j + 2*(i+1)) System.out.print("*"); else System.out.print(" "); } System.out.println(""); } } } }

basking
 2 years ago
Best ResponseYou've already chosen the best response.0The logic is that you want to build i triangles of heights j = 2, 3, 4, ... with row lengths k = 1, 3, 5, 7.... So you use nested for loops (go backwards starting with k).

basking
 2 years ago
Best ResponseYou've already chosen the best response.0(Because you have to center it, it's important to note that the widest part of the tree should be 2*i+1)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.