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edr1c

find all solutions for cos z = 2, z=x+iy?

  • one year ago
  • one year ago

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  1. silvanx
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    2-iy = x

    • one year ago
  2. silvanx
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    2-x/i = y

    • one year ago
  3. silvanx
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    2-x/y = i

    • one year ago
  4. satellite73
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    you need to start with \[\frac{1}{2}(e^{iz}+e^{-iz})=2\]

    • one year ago
  5. satellite73
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    then to \[e^{iz}+e^{-iz}=4\] and then \[e^{2iz}+4e^{iz}+1=0\] solve the quadratic equation in \(e^{iz}\)

    • one year ago
  6. satellite73
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    typo i mean \[e^{2iz}-4e^{iz}+1=0\]

    • one year ago
  7. edr1c
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    ohh. ic. thx.

    • one year ago
  8. satellite73
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    yw

    • one year ago
  9. Aylen333
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    cos never be 2 in maths

    • one year ago
  10. Aylen333
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    -1<cosx<1

    • one year ago
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