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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2you need to start with \[\frac{1}{2}(e^{iz}+e^{iz})=2\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2then to \[e^{iz}+e^{iz}=4\] and then \[e^{2iz}+4e^{iz}+1=0\] solve the quadratic equation in \(e^{iz}\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.2typo i mean \[e^{2iz}4e^{iz}+1=0\]

Aylen333
 2 years ago
Best ResponseYou've already chosen the best response.0cos never be 2 in maths
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