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edr1c

  • 3 years ago

find all solutions for cos z = 2, z=x+iy?

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  1. silvanx
    • 3 years ago
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    2-iy = x

  2. silvanx
    • 3 years ago
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    2-x/i = y

  3. silvanx
    • 3 years ago
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    2-x/y = i

  4. anonymous
    • 3 years ago
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    you need to start with \[\frac{1}{2}(e^{iz}+e^{-iz})=2\]

  5. anonymous
    • 3 years ago
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    then to \[e^{iz}+e^{-iz}=4\] and then \[e^{2iz}+4e^{iz}+1=0\] solve the quadratic equation in \(e^{iz}\)

  6. anonymous
    • 3 years ago
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    typo i mean \[e^{2iz}-4e^{iz}+1=0\]

  7. edr1c
    • 3 years ago
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    ohh. ic. thx.

  8. anonymous
    • 3 years ago
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    yw

  9. Aylen333
    • 3 years ago
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    cos never be 2 in maths

  10. Aylen333
    • 3 years ago
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    -1<cosx<1

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