owenmisa123
[4.06]
Write the equation of the line in slope-intercept form that passes through the points (-2, 6) and (-1, 4).
y = -2x + 5
y = 2x - 3
y = 2x + 6
y = -2x + 2
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owenmisa123
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@Heather_94 @hartnn
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@sauravshakya @satellite73 @sasogeek
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@mathslover
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Help please I think it is the last one
owenmisa123
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@mattfeury
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@TheWriter
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@estudier
sasogeek
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do you know how to find the slope when 2 points are given?
owenmisa123
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Yeah the slope is 2
owenmisa123
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I already did that
owenmisa123
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is the answer the last one
owenmisa123
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@hashsam1
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HELPPPPPPPPPPPPPPPPP
mathslover
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You can verify it @owenmisa123 , did you try to do that?
mathslover
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put the values in the fourth option that you got (y=-2x+1) of :
i) y = 6 and x = -2
y = -2x + 2
ii) y = 4 and x = -1
y =-2x + 2
mathslover
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if you get : LHS + RHS , then you are right
*(LHS --> left hand side and RHS --> Right Hand Side)
sasogeek
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\( \frac{\huge y-4}{\huge x+1}=\huge 2 \)
solve for y
owenmisa123
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thank you guise
ChmE
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The slope is -2, watch your signs
hashsam1
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formula of slope = y2-y1/x2-x1
4-6/-1-(-2) = -2/+1 = -2
y=mx+x = general equation of line
select any one point first and find value of C
4=-1*2 +c
4=-2+c
6=c
now put value of c and m
y=mx+c
y=+2x+6