A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
In the given figure all the surfaces are smooth. The ratio of forces exerted by the wedge on the mass M WHEN F is not applied and when the force F is applied such that M is at rest with respect to the wedge is 
Answers options1,1:2,sec^2 theta,cos^2 theta.
anonymous
 4 years ago
In the given figure all the surfaces are smooth. The ratio of forces exerted by the wedge on the mass M WHEN F is not applied and when the force F is applied such that M is at rest with respect to the wedge is  Answers options1,1:2,sec^2 theta,cos^2 theta.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350498047651:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350584039429:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could you explain a bit how the FBD is drawn with Normal Reaction as mg/cos theta

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sure... there are only two forces on the block in that case... N and mg... the horizontal component of N must be F and the vertical component must be mg

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh . yes i have not got the logic clear.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah whoops, I see why you're asking..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I labelled the theta incorrectly...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350585942860:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there now it works...:)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350586072251:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But what about M at rest ? Is the Normal Reaction force mg/cos theta is sufficient to negate mg sin theta component. I am not so sure whether I have got the concept right. Could you please elaborate. I have got the values right.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0After a second thought it struck me that the wedge is pitted against the Mass M and there is as such no component as mg sin theta...am i correct?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0m is at rest with respect to the ramp when it's accelerating with the ramp...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah I mean, you could decompose mg into vectors along the ramp or into/out of the ramp, but it would be pretty pointless...
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.