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haridas_mandal
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In the given figure all the surfaces are smooth. The ratio of forces exerted by the wedge on the mass M WHEN F is not applied and when the force F is applied such that M is at rest with respect to the wedge is 
Answers options1,1:2,sec^2 theta,cos^2 theta.
 one year ago
 one year ago
haridas_mandal Group Title
In the given figure all the surfaces are smooth. The ratio of forces exerted by the wedge on the mass M WHEN F is not applied and when the force F is applied such that M is at rest with respect to the wedge is  Answers options1,1:2,sec^2 theta,cos^2 theta.
 one year ago
 one year ago

This Question is Closed

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350498047651:dw
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
dw:1350584039429:dw
 one year ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
could you explain a bit how the FBD is drawn with Normal Reaction as mg/cos theta
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
you mean for case 2?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
sure... there are only two forces on the block in that case... N and mg... the horizontal component of N must be F and the vertical component must be mg
 one year ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
Oh . yes i have not got the logic clear.
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
ah whoops, I see why you're asking..
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
I labelled the theta incorrectly...
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
dw:1350585942860:dw
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
there now it works...:)
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
N2 is mg/cos(theta)
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
dw:1350586072251:dw
 one year ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
But what about M at rest ? Is the Normal Reaction force mg/cos theta is sufficient to negate mg sin theta component. I am not so sure whether I have got the concept right. Could you please elaborate. I have got the values right.
 one year ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
After a second thought it struck me that the wedge is pitted against the Mass M and there is as such no component as mg sin theta...am i correct?
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
m is at rest with respect to the ramp when it's accelerating with the ramp...
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
yeah I mean, you could decompose mg into vectors along the ramp or into/out of the ramp, but it would be pretty pointless...
 one year ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
Thanks
 one year ago
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