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haridas_mandal
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In the given figure all the surfaces are smooth. The ratio of forces exerted by the wedge on the mass M WHEN F is not applied and when the force F is applied such that M is at rest with respect to the wedge is 
Answers options1,1:2,sec^2 theta,cos^2 theta.
 2 years ago
 2 years ago
haridas_mandal Group Title
In the given figure all the surfaces are smooth. The ratio of forces exerted by the wedge on the mass M WHEN F is not applied and when the force F is applied such that M is at rest with respect to the wedge is  Answers options1,1:2,sec^2 theta,cos^2 theta.
 2 years ago
 2 years ago

This Question is Closed

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350498047651:dw
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
dw:1350584039429:dw
 2 years ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
could you explain a bit how the FBD is drawn with Normal Reaction as mg/cos theta
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
you mean for case 2?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
sure... there are only two forces on the block in that case... N and mg... the horizontal component of N must be F and the vertical component must be mg
 2 years ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
Oh . yes i have not got the logic clear.
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
ah whoops, I see why you're asking..
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
I labelled the theta incorrectly...
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
dw:1350585942860:dw
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
there now it works...:)
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
N2 is mg/cos(theta)
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
dw:1350586072251:dw
 2 years ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
But what about M at rest ? Is the Normal Reaction force mg/cos theta is sufficient to negate mg sin theta component. I am not so sure whether I have got the concept right. Could you please elaborate. I have got the values right.
 2 years ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
After a second thought it struck me that the wedge is pitted against the Mass M and there is as such no component as mg sin theta...am i correct?
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
m is at rest with respect to the ramp when it's accelerating with the ramp...
 2 years ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.1
yeah I mean, you could decompose mg into vectors along the ramp or into/out of the ramp, but it would be pretty pointless...
 2 years ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
Thanks
 2 years ago
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