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have u done parametric equations?

and do you know cartesian coordinates?

no:/

lets take the feet of the archer to be (0,0)

these are the points i got (0,1.39) (18,8) (45,0) :/

very good..now we need an equation which relates x and y dont we?

yeaah

can u tell me the x-coordinate at any point in time?

hmm, i don't know :/ ? im not very good at math.. ha

understand?

yeah,, kindaa

yeah, there's a diagram , i forgot what their called .. but next to the bulls eye it says A (8cm)

Here is the other post
http://openstudy.com/users/phi#/updates/507e201be4b0919a3cf31396

yess, it is

so you use the picture to find the height of A above the ground
|dw:1350594969329:dw|

I did not explain where the equations come from (it's physics), so it is just showing the math

so all i need to do now would be to use the equation ax^2+bx+c ? & then put the #'s in ?

did you find my write-up (it's an attachment in the 2nd to last post)

yes got it, you are awesomee! <33 i don't know what i would of donee. haha

where did you get the -4.9 from?

I used g= 9.8 m/s^2 in
1/2 g t^2

you have to re-do the numbers. And I notice a typo... but it all changes anyway...

is the 1.035 the mistake?

yes, that should have been 1.35 but now it should be 1.26

yeahh :)
18tanθ + 0.04
where did the 0.04 come from?

nevermind, i know now (:

let me know what you get, and I'll double check it.

what does that zero thing mean after tan ? −18tanθ

which equation number are you looking at?

0 =−18tanθ − 0.04
/18^2
45^2 + 45tanθ +1.39

I labeled this equation (6) so you can refer to it.

i mean like how did you get this -
tanθ =19/1125
= 0.0168

are you working with the new numbers, or just working through the numbers in this old post?

new numbers, haha

what equation do you have now?

i have 0 = 18tan - 0.13 / 18^2? :/

yeaah i have it, i forgot to say that

i actually have for the rest 45^2 + 45 tan + 1.39

yeah :) but then i get confused after that bit because i dont know how you got 19/1125

yes, thank you soo soo much for the help :)

post your results. I'll check back laster.

will do :)

Has anyone figured this out?

not yet, still trying to figure it out :)

how did you get 0.01283...
?

from 0=(1-5/2)tan - 0.13/18 x 5/2 + 1.39/45 :/

so 0.085

I think you missed a decimal place

yeah, haha ..sorry 0.0085 ..so i would use that & the number i said up there^^?

i just got kinda confused :(

just get out your calculator or type it in google:
(-18*77/9000 -0.13)/(18^2)=

-0009765

oooh, Detroit swept the Yankees 4 games to 0. Detroit is off to the World Series

haha, i dont watch that ..but woo for them! :D

you have to be more careful. put in a decimal point, and it is not 9 for the first digit

8 i meaan (:

i mean -0.0008765

so now you have the full equation.

yay ..so do i use the 0.0085 & that?:)

yes

omg, i would of never done this without you

you still have to find the max height of y

yeahh , so i did that next step ..which i got -3.725

How did you find x?

how did i get -3.725? :/

if you have
y = ax^2 +bx+c
you should use x_max= -b/(2a)

yes i used -b/2a to get the answer -3.7

25

maybe you should type out the equation
y = -0.0008765 x^2 + 0.0085 x + 1.39

yess, i wrote that down on my paper :) haha

but i had it the wrong way around :/ oh

yes, I notice you are not careful enough.

im confused on what to do next

y = -0.0008765 x^2 + 0.0085 x + 1.39
type in google
- 0.0085/(2*-0.0008765)=

4.8488

much better. that is the x value where the parabola peaks. what is the y value at that x value?

type this in google
-0.0008765*4.8488^2 + 0.0085*4.8488 + 1.39=

1.41