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hreeg97
Please help me!!!! solve the system using elimination x+ y + +z =1 2x-y+2x=-5 -x+2y-z = 4
[1 1 1 1] [2 -1 2 -5] [-1 2 -1 4] Set up matrix
i have to use elimination
i am so confused on how to do these can someone please help!!!
x+ y +z =1 2x-y+2z=-5 -x+2y-z = 4 x + y+z=1 -x+2y-z=4 3y = 5 2x-y+2z=-5 (-x+2y-z=4)2 -2x -4y-2z = 8 -5y = 3 3y = 5 -5y = 3 -2y = 8 y = -4 ^^^that's your the y part of the ordered triplet, now you just need to find the x and z values
thanks sooooooooo...... much
could you help me with one more?
x+ y + +z =1 2x-y+2x=-5 -x+2y-z = 4 x+ y +z =1 2x-y+2z=-5 3x+3z =-4 (2x-y+2z=-5)2 4x-2y+4z=-10 -x+2y-z = 4 3x+3z=-6 3x+3z=-4 (3x+3z=-6)-1 -3x-3z=6 0 does not equal 2, so there is no solution for the problem