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anonymous
 4 years ago
Please help me!!!!
solve the system using elimination
x+ y + +z =1
2xy+2x=5
x+2yz = 4
anonymous
 4 years ago
Please help me!!!! solve the system using elimination x+ y + +z =1 2xy+2x=5 x+2yz = 4

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Hero
 4 years ago
Best ResponseYou've already chosen the best response.0[1 1 1 1] [2 1 2 5] [1 2 1 4] Set up matrix

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have to use elimination

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am so confused on how to do these can someone please help!!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x+ y +z =1 2xy+2z=5 x+2yz = 4 x + y+z=1 x+2yz=4 3y = 5 2xy+2z=5 (x+2yz=4)2 2x 4y2z = 8 5y = 3 3y = 5 5y = 3 2y = 8 y = 4 ^^^that's your the y part of the ordered triplet, now you just need to find the x and z values

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks sooooooooo...... much

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could you help me with one more?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x+ y + +z =1 2xy+2x=5 x+2yz = 4 x+ y +z =1 2xy+2z=5 3x+3z =4 (2xy+2z=5)2 4x2y+4z=10 x+2yz = 4 3x+3z=6 3x+3z=4 (3x+3z=6)1 3x3z=6 0 does not equal 2, so there is no solution for the problem
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