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hreeg97

  • 2 years ago

Please help me!!!! solve the system using elimination x+ y + +z =1 2x-y+2x=-5 -x+2y-z = 4

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  1. Hero
    • 2 years ago
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    [1 1 1 1] [2 -1 2 -5] [-1 2 -1 4] Set up matrix

  2. hreeg97
    • 2 years ago
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    i have to use elimination

  3. Hero
    • 2 years ago
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    Good luck with that

  4. hreeg97
    • 2 years ago
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    i am so confused on how to do these can someone please help!!!

  5. lainey.ressler
    • 2 years ago
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    x+ y +z =1 2x-y+2z=-5 -x+2y-z = 4 x + y+z=1 -x+2y-z=4 3y = 5 2x-y+2z=-5 (-x+2y-z=4)2 -2x -4y-2z = 8 -5y = 3 3y = 5 -5y = 3 -2y = 8 y = -4 ^^^that's your the y part of the ordered triplet, now you just need to find the x and z values

  6. hreeg97
    • 2 years ago
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    thanks sooooooooo...... much

  7. hreeg97
    • 2 years ago
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    could you help me with one more?

  8. lainey.ressler
    • 2 years ago
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    x+ y + +z =1 2x-y+2x=-5 -x+2y-z = 4 x+ y +z =1 2x-y+2z=-5 3x+3z =-4 (2x-y+2z=-5)2 4x-2y+4z=-10 -x+2y-z = 4 3x+3z=-6 3x+3z=-4 (3x+3z=-6)-1 -3x-3z=6 0 does not equal 2, so there is no solution for the problem

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