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hreeg97
Group Title
Please help me!!!!
solve the system using elimination
x+ y + +z =1
2xy+2x=5
x+2yz = 4
 one year ago
 one year ago
hreeg97 Group Title
Please help me!!!! solve the system using elimination x+ y + +z =1 2xy+2x=5 x+2yz = 4
 one year ago
 one year ago

This Question is Closed

Hero Group TitleBest ResponseYou've already chosen the best response.0
[1 1 1 1] [2 1 2 5] [1 2 1 4] Set up matrix
 one year ago

hreeg97 Group TitleBest ResponseYou've already chosen the best response.0
i have to use elimination
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
Good luck with that
 one year ago

hreeg97 Group TitleBest ResponseYou've already chosen the best response.0
i am so confused on how to do these can someone please help!!!
 one year ago

lainey.ressler Group TitleBest ResponseYou've already chosen the best response.1
x+ y +z =1 2xy+2z=5 x+2yz = 4 x + y+z=1 x+2yz=4 3y = 5 2xy+2z=5 (x+2yz=4)2 2x 4y2z = 8 5y = 3 3y = 5 5y = 3 2y = 8 y = 4 ^^^that's your the y part of the ordered triplet, now you just need to find the x and z values
 one year ago

hreeg97 Group TitleBest ResponseYou've already chosen the best response.0
thanks sooooooooo...... much
 one year ago

hreeg97 Group TitleBest ResponseYou've already chosen the best response.0
could you help me with one more?
 one year ago

lainey.ressler Group TitleBest ResponseYou've already chosen the best response.1
x+ y + +z =1 2xy+2x=5 x+2yz = 4 x+ y +z =1 2xy+2z=5 3x+3z =4 (2xy+2z=5)2 4x2y+4z=10 x+2yz = 4 3x+3z=6 3x+3z=4 (3x+3z=6)1 3x3z=6 0 does not equal 2, so there is no solution for the problem
 one year ago
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