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Firejay5
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Simplify. Assume that no variable = 0. I got
28x^4 over y^2
26. (7x^3y^5) (4x^1y^3)
 one year ago
 one year ago
Firejay5 Group Title
Simplify. Assume that no variable = 0. I got 28x^4 over y^2 26. (7x^3y^5) (4x^1y^3)
 one year ago
 one year ago

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Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
is that right really
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
We learned this today, so I have more like 12 like that, but I need help on 1/2 of them. I don't really get it that much
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
most of them are easy to you, but complex to me
 one year ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
it will make sense in time
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
what do you mean
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
will you help me
 one year ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
yes but I dont have much time
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
why got to go to bed
 one year ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
gotta eat dinner :)
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
can you do at least 2 of the 6
 one year ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
sure, but I might have to leave in the middle and then come back later to finish
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
30. 2x^2(6y^3)(2x^2y) 32. \[\frac{ 5x^3y^3z^4 }{ 20x^3y^4z^4 }\]
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
on the bottom it's suppose to be y to the 4 power
 one year ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
got it, I have to go eat now, but I can help when I get back, or I'm sure someone else can help if you dont have much time
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
I have time
 one year ago
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