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Firejay5
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Simplify. Assume that no variable = 0. I got
28x^4 over y^2
26. (7x^3y^5) (4x^1y^3)
 2 years ago
 2 years ago
Firejay5 Group Title
Simplify. Assume that no variable = 0. I got 28x^4 over y^2 26. (7x^3y^5) (4x^1y^3)
 2 years ago
 2 years ago

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Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
is that right really
 2 years ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
We learned this today, so I have more like 12 like that, but I need help on 1/2 of them. I don't really get it that much
 2 years ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
most of them are easy to you, but complex to me
 2 years ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
it will make sense in time
 2 years ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
what do you mean
 2 years ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
will you help me
 2 years ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
yes but I dont have much time
 2 years ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
why got to go to bed
 2 years ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
gotta eat dinner :)
 2 years ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
can you do at least 2 of the 6
 2 years ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
sure, but I might have to leave in the middle and then come back later to finish
 2 years ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
30. 2x^2(6y^3)(2x^2y) 32. \[\frac{ 5x^3y^3z^4 }{ 20x^3y^4z^4 }\]
 2 years ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
on the bottom it's suppose to be y to the 4 power
 2 years ago

tjones89 Group TitleBest ResponseYou've already chosen the best response.0
got it, I have to go eat now, but I can help when I get back, or I'm sure someone else can help if you dont have much time
 2 years ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.0
I have time
 2 years ago
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