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Consider the isosceles triangle with AB = AC. Suppose the angle bisector of B intersects the side AC at D and that BC = BD + AD. Determine the angle A.
 one year ago
 one year ago
Consider the isosceles triangle with AB = AC. Suppose the angle bisector of B intersects the side AC at D and that BC = BD + AD. Determine the angle A.
 one year ago
 one year ago

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JoãoVitorMCBest ResponseYou've already chosen the best response.0
dw:1350605708301:dw
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Wanna use trig, or regular plane geometry?
 one year ago

JoãoVitorMCBest ResponseYou've already chosen the best response.0
the easiest way to solve this
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
I was looking at this last night. I'm trying to find my notes on it.
 one year ago

JoãoVitorMCBest ResponseYou've already chosen the best response.0
ok, i'm trying to solve this, but this one is really hard...
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Yeah, I'm trying combinations of law of cosines and law of sines.
 one year ago

estudierBest ResponseYou've already chosen the best response.2
dw:1350693786588:dw
 one year ago

estudierBest ResponseYou've already chosen the best response.2
I will have to make a better drawing.....Answer s/b 100, I think....
 one year ago

estudierBest ResponseYou've already chosen the best response.2
dw:1350694614179:dw
 one year ago

JoãoVitorMCBest ResponseYou've already chosen the best response.0
what is "s/b 100"?
 one year ago

JoãoVitorMCBest ResponseYou've already chosen the best response.0
thank you so much!
 one year ago

JoãoVitorMCBest ResponseYou've already chosen the best response.0
hey where you get this 180° 5(Betha) = 4(Betha) ?
 one year ago

JoãoVitorMCBest ResponseYou've already chosen the best response.0
yes but i still don't see how to get 4 Beta...
 one year ago

JoãoVitorMCBest ResponseYou've already chosen the best response.0
but them you set this equal to 4 beta, then i'm lost...
 one year ago

JoãoVitorMCBest ResponseYou've already chosen the best response.0
thank you soo much!
 one year ago
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