JoãoVitorMC

Consider the isosceles triangle with AB = AC. Suppose the angle bisector of B intersects the side AC at D and that BC = BD + AD. Determine the angle A.

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JoãoVitorMC

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|dw:1350605708301:dw|

CliffSedge

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Wanna use trig, or regular plane geometry?

JoãoVitorMC

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the easiest way to solve this

CliffSedge

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I was looking at this last night. I'm trying to find my notes on it.

JoãoVitorMC

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ok, i'm trying to solve this, but this one is really hard...

CliffSedge

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Yeah, I'm trying combinations of law of cosines and law of sines.

JoãoVitorMC

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but nothing yet

estudier

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|dw:1350693786588:dw|

estudier

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I will have to make a better drawing.....Answer s/b 100, I think....

estudier

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|dw:1350694614179:dw|

JoãoVitorMC

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what is "s/b 100"?

estudier

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should be

JoãoVitorMC

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ohh ok i got it

JoãoVitorMC

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thank you so much!

estudier

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yw:-)

JoãoVitorMC

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hey where you get this 180° -5(Betha) = 4(Betha) ?

estudier

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ADB is 3 Beta

JoãoVitorMC

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yes but i still don't see how to get 4 Beta...

estudier

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look at triangle AED

estudier

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For 180-5 Beta.

JoãoVitorMC

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yes that i got

JoãoVitorMC

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but them you set this equal to 4 beta, then i'm lost...

estudier

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BD = BE so 4 Beta

JoãoVitorMC

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ohhhh now i see

JoãoVitorMC

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thank you soo much!

estudier

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yw:-)