juciystar234
Need help subtracting fractions (fractions below)
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juciystar234
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|dw:1350605790593:dw|
juciystar234
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ifunfrank
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make them into an improper fraction first
juciystar234
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so like I did kinda?
ifunfrank
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no. make them improper fractions by taking away the whole number.
So the first mixed number would turn into 46/3 and the second one would turn into 19/2
juciystar234
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Ok hod on
juciystar234
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ifunfrank
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yeah! :)
Do you know how did i converted them from mixed to improper though? :o
ifunfrank
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*convert
juciystar234
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juciystar234
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Yes I actually did that myself I didn't see your answers til' I finished :)
ifunfrank
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exactly! now just subtract the numerators and turn it back into a mixed number :)
juciystar234
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juciystar234
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Right?
ifunfrank
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okay, now turn it back to a mixed number if it's asked :)
juciystar234
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No it's not asked. So I would leave it like that?
juciystar234
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6 35/6
ifunfrank
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ummm, i guess you should turn it back into a mixed number since the problem was given to you as a mixed number
ifunfrank
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mmm, no. the your answer for the mixed number is incorrect
juciystar234
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oh thanks
ifunfrank
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your final answer would be \[5 \frac{ 5 }{ 6}\]
petewe
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or, just ignore the fraction first, add the whole numbers then add the fractions.
juciystar234
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um okk........
petewe
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converting them to improper form is unnecessary and tedious.
just do (15-9) + [(1/3) - (1/2)]
petewe
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Algebraically, you can say:
let a = first constant
let b = first fraction
let c = second constant
let d = second fraction
(a-c) + (b-d)
juciystar234
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ok but wouldn't you have to make 1/3 and 1/2 make the denominators 6