## juciystar234 3 years ago Need help subtracting fractions (fractions below)

1. juciystar234

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2. juciystar234

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3. ifunfrank

make them into an improper fraction first

4. juciystar234

so like I did kinda?

5. ifunfrank

no. make them improper fractions by taking away the whole number. So the first mixed number would turn into 46/3 and the second one would turn into 19/2

6. juciystar234

Ok hod on

7. juciystar234

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8. ifunfrank

yeah! :) Do you know how did i converted them from mixed to improper though? :o

9. ifunfrank

*convert

10. juciystar234

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11. juciystar234

Yes I actually did that myself I didn't see your answers til' I finished :)

12. ifunfrank

exactly! now just subtract the numerators and turn it back into a mixed number :)

13. juciystar234

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14. juciystar234

Right?

15. ifunfrank

okay, now turn it back to a mixed number if it's asked :)

16. juciystar234

No it's not asked. So I would leave it like that?

17. juciystar234

6 35/6

18. ifunfrank

ummm, i guess you should turn it back into a mixed number since the problem was given to you as a mixed number

19. ifunfrank

20. juciystar234

oh thanks

21. ifunfrank

your final answer would be $5 \frac{ 5 }{ 6}$

22. petewe

or, just ignore the fraction first, add the whole numbers then add the fractions.

23. juciystar234

um okk........

24. petewe

converting them to improper form is unnecessary and tedious. just do (15-9) + [(1/3) - (1/2)]

25. petewe

Algebraically, you can say: let a = first constant let b = first fraction let c = second constant let d = second fraction (a-c) + (b-d)

26. juciystar234

ok but wouldn't you have to make 1/3 and 1/2 make the denominators 6