Need help subtracting fractions (fractions below)

- anonymous

Need help subtracting fractions (fractions below)

- jamiebookeater

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- anonymous

|dw:1350605790593:dw|

- anonymous

|dw:1350605879888:dw|

- anonymous

make them into an improper fraction first

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## More answers

- anonymous

so like I did kinda?

- anonymous

no. make them improper fractions by taking away the whole number.
So the first mixed number would turn into 46/3 and the second one would turn into 19/2

- anonymous

Ok hod on

- anonymous

|dw:1350606267545:dw|

- anonymous

yeah! :)
Do you know how did i converted them from mixed to improper though? :o

- anonymous

*convert

- anonymous

|dw:1350606330718:dw|

- anonymous

Yes I actually did that myself I didn't see your answers til' I finished :)

- anonymous

exactly! now just subtract the numerators and turn it back into a mixed number :)

- anonymous

|dw:1350606430700:dw|

- anonymous

Right?

- anonymous

okay, now turn it back to a mixed number if it's asked :)

- anonymous

No it's not asked. So I would leave it like that?

- anonymous

6 35/6

- anonymous

ummm, i guess you should turn it back into a mixed number since the problem was given to you as a mixed number

- anonymous

mmm, no. the your answer for the mixed number is incorrect

- anonymous

oh thanks

- anonymous

your final answer would be \[5 \frac{ 5 }{ 6}\]

- anonymous

or, just ignore the fraction first, add the whole numbers then add the fractions.

- anonymous

um okk........

- anonymous

converting them to improper form is unnecessary and tedious.
just do (15-9) + [(1/3) - (1/2)]

- anonymous

Algebraically, you can say:
let a = first constant
let b = first fraction
let c = second constant
let d = second fraction
(a-c) + (b-d)

- anonymous

ok but wouldn't you have to make 1/3 and 1/2 make the denominators 6

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