## Firejay5 3 years ago Simplify. 30. 2x^2(6y^3)(2x^2y) 32. −5x3y3z420x3y−4z4

1. Firejay5

$\frac{ -5x^3y^3z^4 }{ 20x^3y^7z^4 }$

2. Firejay5

Is #32

3. Sheng

|dw:1350606375165:dw|

4. Sheng

y^4 * 128 = -1 y^4 = -1/128 take 4th root for answer

5. Firejay5

what number are you doing 30 or 32

6. Firejay5

This is monomials

7. tjones89

$-\frac{ 5x^2y^3z^4 }{ 20x^3y^7z^4 } = -\frac{ 5 }{ 20 }\times \frac{ x^2 }{ x^3 }\times \frac{ y^3 }{ y^7 }\times \frac{ z^4 }{ z^4}$

8. tjones89

$\frac{ x^2 }{ x^3 } = x^2x ^{-3} = x ^{2-3}$

9. tjones89

$= x ^{-1} = \frac{ 1 }{ x }$

10. tjones89

use these steps for each one of those terms: $\frac{ y^3 }{ y^7 }$ $\frac{ z^4 }{ z^4 }$ and then put them all together

11. Firejay5

I got $\frac{ - 1 }{ 4 }$ x^1y^4z^1

12. Firejay5

is that it

13. Sheng

oh i thought you mean whole equation = 32... then answer is just -1/4y^4

14. Sheng

all the x terms, z terms cancel

15. tjones89

not quite, the exponents on x and y should be negative, or you should put them in the denominator of your final answer like this $-\frac{ 1 }{ 4xy^4 }$ or $-\frac{ x ^{-1}y ^{-4} }{ 4 }$

16. tjones89

and yes $\frac{ z ^{4} }{ z^4 } = 1$ so it cancels

17. Firejay5

you can divide the exponents or subtract the exponents or both whenever you divide a fraction

18. tjones89

another way to look at dividing variables with exponents...|dw:1350609282625:dw|

19. Sheng

the x exponents cancel, why are you leaving them in? it's not a 2 on top, it's x^3

20. Firejay5

@tjones89 Actually both x's are 3s just looks like its a 2

21. tjones89

hah you're right, its really small print...

22. Firejay5

yes so x's would be x^1 or x^0

23. tjones89

x^2/x^2 = x^2-2 = x^0 = 1

24. Firejay5

x^3/x^3 = x^1 or X^3 - x^3 = 0

25. Firejay5

x^0

26. tjones89

did you mean to put divide instead of subtract for x^3 - x^3?

27. Firejay5

you can divide or subtract depending on the number

28. Firejay5

like if it's the same you divide and if its different you subtract the big from little( 8-5)