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Firejay5
 3 years ago
Simplify.
30. 2x^2(6y^3)(2x^2y)
32.
−5x3y3z420x3y−4z4
Firejay5
 3 years ago
Simplify. 30. 2x^2(6y^3)(2x^2y) 32. −5x3y3z420x3y−4z4

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Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 5x^3y^3z^4 }{ 20x^3y^7z^4 }\]

Sheng
 3 years ago
Best ResponseYou've already chosen the best response.0y^4 * 128 = 1 y^4 = 1/128 take 4th root for answer

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0what number are you doing 30 or 32

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 5x^2y^3z^4 }{ 20x^3y^7z^4 } = \frac{ 5 }{ 20 }\times \frac{ x^2 }{ x^3 }\times \frac{ y^3 }{ y^7 }\times \frac{ z^4 }{ z^4}\]

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ x^2 }{ x^3 } = x^2x ^{3} = x ^{23}\]

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0\[ = x ^{1} = \frac{ 1 }{ x }\]

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0use these steps for each one of those terms: \[\frac{ y^3 }{ y^7 }\] \[\frac{ z^4 }{ z^4 }\] and then put them all together

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0I got \[\frac{  1 }{ 4 }\] x^1y^4z^1

Sheng
 3 years ago
Best ResponseYou've already chosen the best response.0oh i thought you mean whole equation = 32... then answer is just 1/4y^4

Sheng
 3 years ago
Best ResponseYou've already chosen the best response.0all the x terms, z terms cancel

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0not quite, the exponents on x and y should be negative, or you should put them in the denominator of your final answer like this \[\frac{ 1 }{ 4xy^4 }\] or \[\frac{ x ^{1}y ^{4} }{ 4 }\]

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0and yes \[\frac{ z ^{4} }{ z^4 } = 1 \] so it cancels

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0you can divide the exponents or subtract the exponents or both whenever you divide a fraction

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0another way to look at dividing variables with exponents...dw:1350609282625:dw

Sheng
 3 years ago
Best ResponseYou've already chosen the best response.0the x exponents cancel, why are you leaving them in? it's not a 2 on top, it's x^3

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0@tjones89 Actually both x's are 3s just looks like its a 2

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0hah you're right, its really small print...

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0yes so x's would be x^1 or x^0

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0x^2/x^2 = x^22 = x^0 = 1

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0x^3/x^3 = x^1 or X^3  x^3 = 0

tjones89
 3 years ago
Best ResponseYou've already chosen the best response.0did you mean to put divide instead of subtract for x^3  x^3?

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0you can divide or subtract depending on the number

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0like if it's the same you divide and if its different you subtract the big from little( 85)
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